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Microprocessor Articles
Page 36 of 42
8085 Assembly language program to find largest number in an array
In this program we will see how to find the largest number from a block of bytes using 8085.Problem StatementWrite 8085 Assembly language program to find the largest number from a block of bytes.DiscussionIn this program the data are stored at location 8001H onwards. The 8000H is containing the size of the block. After executing this program, it will return the largest number and store it at location 9000H.Logic is simple, we are taking the first number at register B to start the job. In each iteration we are getting the number from memory and storing it into register A. ...
Read More8085 program to generate Fibonacci sequence
In this program we will see how to generate Fibonacci sequence.Problem StatementWrite 8085 Assembly language program to generate the first ten elements of the Fibonacci sequence using registers only and store them in memory locations 8050H to 8059H. DiscussionThis program will generate the Fibonacci numbers. The Fibonacci numbers follows this relation F(i) = F(i - 1) + F(i - 2) for all i >2 with F(1) = 0, F(2) = 1.InputIn this case we are not providing any input, this program will generate ten Fibonacci numbers.Flow DiagramProgramAddressHEX CodesLabelsMnemonicsComments800021, 50, 80STARTLXI H 8050H Pointer to the OUT-BUFFER8003AFXRA A Clear accumulator and reg. B800447MOV B, ...
Read More8085 Program to perform bubble sort in descending order
In this program we will see how to sort a block of bytes in descending order using bubble sorting technique.Problem StatementWrite8085 Assembly language program to sort numbers in descending order where n number of numbers are stored in consecutive memory locations starting from 8041H and the value of n is available in memory location 8040H (Using BUBBLE sort).DiscussionIn this program we will arrange the numbers in bubble sorting technique. In this sorting technique, it will be executed in different pass. In each pass the smallest number is stored at the end of the list. Here we are taking the numbers ...
Read More8085 Program to convert BCD to HEX
In this program we will see how to convert BCD numbers to binary equivalent.Problem StatementA BCD number is stored at location 802BH. Convert the number into its binary equivalent and store it to the memory location 802CH.DiscussionIn this problem we are taking a BCD number from the memory and converting it to its binary equivalent. At first we are cutting each nibble of the input. So if the input is 52 (0101 0010) then we can simply cut it by masking the number by 0FH and F0H. When the Higher order nibble is cut, then rotate it to the left ...
Read More8085 Program to convert HEX to BCD
In this program we will see how to convert binary numbers to its BCD equivalent.Problem StatementA binary number is store dat location 800H. Convert the number into its BCD equivalent and store it to the memory location 8050H.DiscussionHere we are taking a number from the memory, and initializing it as a counter. Now in each step of this counter we are incrementing the number by 1, and adjust the decimal value. By this process we are finding the BCD value of binary number or hexadecimal number.We can use INRinstruction to increment the counter in this case but this instruction will ...
Read More8085 Program to Divide a 16-bit number by an 8-bit number
In this program we will see how to divide a 16-bit number by an 8-bit numberProblem StatementWrite 8085 Assembly language program to divide a 16-bit number by an 8-bit number.DiscussionIn this program we are taking the 16-bit number from 8000H and 8001H. The 8000H is holding the lower order byte and 8001H is holding higher order byte. The8002H is holding the 8-bit numerator. After dividing the number the16-bit quotient is stored at location 8050H and 8051H. The remainderis stored at 8052H.InputAddressData......80002B8001CA800253......Flow DiagramProgramAddressHEX CodesLabelsMnemonicsCommentsF00021, 00, 80LXI H, 8000HPoint 8000HaddressF0037EMOV A, MStore the lower order byteF00423INX H Increase the HL pair to ...
Read More8085 Program to perform linear search
In this program we will see how to search an element in a block of bytes using 8085.Problem StatementWrite 8085 Assembly language program to search a key value in a block of data using linear search technique.DiscussionIn this program the data are stored at location 8002H to 8007H. The 8000H is containing the size of the block, and 8001H is holding the key value to search.After executing this program, it will return the address of the data where the item is found and store the address at location 9000H and9001H. If the item is not found, it will return FFFFH.If ...
Read More8085 Program to find the smallest number
In this program we will see how to find the smallest number from a block of bytes using 8085.Problem StatementWrite 8085 Assembly language program to find the smallest number from a block of bytes.DiscussionIn this program the data are stored at location 8001H onwards. The 8000H is containing the size of the block. After executing this program, it will return the smallest number and store it at location 9000H.Logic is simple, we are taking the first number at register B to start the job. In each iteration we are getting the number from memory and storing it into register A. ...
Read More8085 Program to find the HCF of two given bytes
In this program we will see how to find the HCF or GCD of two numbers using 8085.Problem StatementWrite 8085 Assembly language program to find the HCF of two numbers stored at memory location 8000H and 8001H.DiscussionThis problem is solved by the Euclidean algorithm to find HCF. This algorithm is very simple.The algorithm steps are as follows −If first number and second number are same, thengo to step 3.Else if first number < second number, then exchange no1 andno2.first-number A, then exchange B and AF00D90SUB B if B < A, subtract B from AF00EC3, 06, F0JMP LOOP Jump to LOOPF01148EXGMOV ...
Read More8085 Program to convert ASCII to binary
Now let us see a program of Intel 8085 Microprocessor. This program will convert ASCII to binary values.Problem StatementWrite 8085 Assembly language program to convert ASCII to binary or Hexadecimal character values. DiscussionWe know that the ASCII of number 00H is 30H (48D), and ASCII of 09H is39H (57D). So all other numbers are in the range 30H to 39H. The ASCII value of 0AH is 41H (65D) and ASCII of 0FH is 46H (70D), so all other alphabets (B, C, D, E, F) are in the range 41H to 46H.Here the logic is simple. We are checking whether the ASCII ...
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