Article Categories
- All Categories
-
Data Structure
-
Networking
-
RDBMS
-
Operating System
-
Java
-
MS Excel
-
iOS
-
HTML
-
CSS
-
Android
-
Python
-
C Programming
-
C++
-
C#
-
MongoDB
-
MySQL
-
Javascript
-
PHP
Microcontroller Articles
Page 16 of 33
Read and Write the stack in 8085 Microprocessor
Reading from the StackLet us consider that SP contents the address FC78H, and we want to read information from a stack location. In this case, we are not interested in reading from a location whose address is less than the memory address present in SP. This is because 8085 interprets them as useless information. For example, there is no point in reading useless information from memory location FC75H.SP interprets that, memory locations FC78H, FC79H, ..., FFFFH are all interpreted by 8085 to have useful information. To read from Stack, the instruction is POP in 8085 microprocessor instruction set. Here we ...
Read MoreDifference between call and jump instructions in 8085 Microprocessor
The main differences between a JMP instruction and a CALL instruction is as follows –If a JMP instruction is executed, we jump to the destination location, and the execution carries on from there, without bothering to come back later to the instruction after the JMP. On the other hand, if a CALL instruction is executed, we jump to the subroutine, and the execution carries on from there till the RET instruction is executed in the subroutine, and then we come back to the instruction after the CALL in the main program.The address of the next instruction after the CALL instruction ...
Read More8085 Program to simulate decimal up counter
Now let us see a program of Intel 8085 Microprocessor. In this program we will see how to simulate the decimal up counter.Problem Statement:Write 8085 Assembly language program to simulate decimal up counter.Discussion:In this section we are simulating the decimal up counter. Here the counter will count 100 decimal numbers from 0 to 99. All values will be updated in each 0.5 seconds. For decimal count we are using the DAA instruction.Note: Here for simplicity we are storing the numbers into memory. To simulate it like a counter we can use 7-segment display to show the numbersInput:Here we are not ...
Read MoreCreation of .ASM file using a text editor
The program written in assembly language is entered by us by the help of any editor, we prefer a screen editor because when we enter the program it is of no importance for the particular exact column label of instructions and the starting of the program. But the point to be noted that the instruction must start after column 1. More over the aligned program must be lucidly written for reading if its various fields should be assigned properly. There are many features which the editor provides like many help features which the user gets to be more familiar by ...
Read MorePrompt mode in 8085 Microprocessor
We have seen previously that the linker is invoked in three modes i.e. they are command line mode, prompt mode and data file mode. In the Prompt mode the linker is run by simply typing the ‘LINK85’. Responding to the prompt the linker requests the user for the file name. In the given example, responding with ‘MULT.OBJ’ is there in fact MULT is enough.The linker prompts for the address of the offset. The value of the offset which is input by means of the user is finally added to the value of any ORG statements in the file. In response ...
Read More8085 Program to Subtract two multi-Byte numbers
Now let us see a program of Intel 8085 Microprocessor. This program is mainly for subtracting multi Byte numbers.Problem Statement:Write 8085 Assembly language program to add two multi-Byte numbers.Discussion:We are using 3-Byte numbers. The numbers are stored into the memory at location 8001H and 8004H. One additional information is stored at location 8000H. In this place we are storing the Byte count. The result is stored at location 8050H.We are taking the address of first operand block address into DE register pair, and the second operand block address into HL pair. The BC register pair is storing the destination address ...
Read MoreGeneration of time delay in 8085
In this section we will see how to generate the time delay using 8085 programs. The delay will be used in different places to simulate clocks, or counters or some other area.When the delay subroutine is executed, the microprocessor does not execute other tasks. For the delay we are using the instruction execution times. executing some instructions in a loop, the delay is generated. There are some methods of generating delays. These methods are as follows.Using NOP instructionsUsing 8-bit register as counterUsing 16-bit register pair as counter.Using NOT instructions:One of the main usage of NOP instruction is in delay generation. ...
Read MoreChip Select Logic in 8085 Microprocessor
The master of microcomputer system is the microprocessor since all the operations of a computer are controlled by the microprocessor, the control unit often called as (CU) is found in the microprocessor. In the microcomputer system apart from processor there are several chips of RAM, CHIPS of EPROM and other Input Output port chips, timer 8253 is also present. But surprisingly at any moment of time the remains with only one of the chip. By activation of the chip selection the processor, the selection of the chip of the processor is done. Hence except the processor all chips must have ...
Read More8085 Program to simulate decimal down counter
Now let us see a program of Intel 8085 Microprocessor. In this program we will see how to simulate the decimal down counter.Problem Statement:Write 8085 Assembly language program to simulate decimal down counter.Discussion:In this section we are simulating the decimal down counter. Here the counter will count 100 decimal numbers from 99 to 0. All values will be updated in each 0.5 seconds. For decimal count we are using the DAA instruction.Note: Here for simplicity we are storing the numbers into memory. To simulate it like a counter we can use 7-segment display to show the numbersInput:Here we are not ...
Read MorePin details and its address range in 8085 Microprocessor
Let us assume that we have a RAM chip of 2K x 8, It signifies that, we have 2 x 1024 = 2048 memory locations having information of 8 bits at each location. For selecting one of 2K = 211 memory locations in chip, there should be exactly input pins of 11 address lines. For bidirectional data transfer scheme, there should be eight pin involved in this process. The processor action involved in it is signified by the input pins RD* and WR*. Two pins are specified for grounding process of the pin and connecting of Direct Current of +5 ...
Read More