OK, there are lots of problems with coming up with a theory of quantum gravity. The particular one we’re going to discuss in this series of posts is the non-quadracity of the free part of the Lagrangian for the general theory of relativity.
Put simply, all the classic theories of quantum mechanics, including QED and QCD, have a ‘free’, non-interacting part of the Lagrangian which is quadratic in the fields, and quadratic Lagrangians -> Gaussian integrals -> good times, as Gaussian integrals are basically the only ones we can solve explicitly. However, the Lagrangian for general relativity is not quadratic in the relevant fields, and this becomes a bit of a pain if we want to solve anything analytically.
In this series of posts we’ll dive into this, do some approximations, and see if we can find anything that will help.
First off, this Lagrangian: the Lagrangian for general relativity takes the pretty simple form , where
is the metric (with components
and components of its inverse
) and
is the Ricci tensor:
,
which can be written in terms of the metric and its inverse as
,
which also highlights that throughout these posts we shall we switching freely between using and
to represent the partial derivative of
with respect to
.
We can immediately see that the Lagrangian is a horribly non-linear second-order partial differential equation in . We’re not even going to try playing with the Lagrangian in its raw form: instead, we’re going to try the simplest and easiest approximation we can think of, which is to expand the Lagrangian in terms of small perturbations of the metric about a Minkowski background,
, where all
, so
.
Because quantum theories that are quadratic in their fields are at least a bit easier to solve, we’re going to expand up to quadratic terms in
. Let’s get started!
Manipulations
,
which is an exact relationship, which is a good start. For simplicity we identify these two terms as
,
with the superscript (1) and (2) referring to the corresponding powers of .
Keeping terms just up to second order in , this results in the Ricci tensor looking like
.
Multiplying by results in
.
The remaining component of the Lagrangian is the (square-root of) the determinant of the metric. Now using , and the Taylor series definition
,
along with , we get that
,
where is the trace of the metric variation.
We’re now ready to write down our quadratic expression for the Lagrangian,
,
where
and
.
Linearised EFE
We have a quadratic Lagrangian now, and can begin to make progress on solving the theory. But first, let’s check that our Lagrangian reproduces a known result, the linearised Einstein Field Equations.
The Einstein Field Equations are the equations of motion of the Lagrangian, given by
.
First, let us define some useful derivatives:
,
,
,
.
Now, to make progress on the equations of motion, we break the required analysis up into terms of different order and first analyse .
The first term is simple: . The second term can be expanded and analysed without too much difficult, getting
Note that this term is not zero, so the linear term in the Lagrangian is giving a contribution to the classical solution of the theory.
The second-order contribution is more complex:
but maintaining only terms linear in we find
Now to leading order in we have that
, so bringing everything together we find
.
Writing the d’Alembert operator this can be written to leading order in
as
,
which agrees with the form of the linearised EFE on, for example, Wikipedia, up to an overall sign.
Great success! Our quadratic Lagrangian successfully recreates the linear equations of motion, and so can be used to derive effects like gravitational waves. In the next post we will move on to examine this quadratic Lagrangian in more detail, and attempting to create a proper quantum theory.


