python33, UnicodeEncodeError, how to ignore error

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  • gintare
    New Member
    • Mar 2007
    • 103
    #1

    python33, UnicodeEncodeError, how to ignore error

    I want that my script would continue running despite the error.

    Code:
    fw=open(fname,'r',encoding='utf-8')
bhtml=str(fw.readlines())
soup=BeautifulSoup(bhtml)
for tagdiv in soup.find_all("div", class_="hw_txt"):
    word=tagdiv.get_text()
    print(" replace word=",repr(word)) #gives error, interrupts script
    print(" replace word=",word ).decode("utf-8","ignore")  #gives error, interrupts script
    try:
        print(" replace word=",word)
    except IOError:
        pass
    #gives error, interrupts script
    Tags: None
    • bvdet
      Recognized Expert Specialist
      • Oct 2006
      • 2851
      #2
      Encapsulate the offending line in another try/except block.

        Comment

        • dwblas
          Recognized Expert Contributor
          • May 2008
          • 626
          #3
          The first 2 print statements will yield an error because the are not in a try/except. The last print statement will error out for anything other than an IO error. Putting the entire block in a try except will let the code run but may or may not allow you to trace the errors.

          Also see this link for the correct use of decode http://www.tutorialspoint.com/python/string_decode.htm (decoding the return value from a print function will not yield anythng useful)
          Code:
          import traceback

try:
    fw=open(fname,'r',encoding='utf-8')
    bhtml=str(fw.readlines())
    soup=BeautifulSoup(bhtml)
    for tagdiv in soup.find_all("div", class_="hw_txt"):
        word=tagdiv.get_text()
        print(" replace word=",repr(word))
        print(" replace word=",word ).decode("utf-8","ignore")
        print(" replace word=",word)
except:
    traceback.print_exc()
##    raise  ## uncomment to cause the program to stop on an error

            Comment

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