Array input

**chaarmann** · Sep 25 '17, 10:44 AM

Please show us what you have written so far and where you are stuck.

**Bekir** · Sep 25 '17, 11:44 AM

Code:

package dan1;

import java.util.Scanner;

public class Nizovi6 {
	public static void main(String [] args){
		Scanner scanner = new Scanner(System.in);
		int n = scanner.nextInt();
		int [] index = new int [n];
		int [] score = new int [n];
		for(int i = 0;i < n;i++){
			index[i] = scanner.nextInt();
			score[i] = scanner.nextInt();
		}
		for(int i = 0;i<n;i++){
			for(int j =0;j < n; j++){
				if(score[i] > score[j]){
					int t = score[j];
					score[j] = score[i];
					score[i] = t;
				}
			}
		}
		for(int i = 0; i <n;i++){
			System.out.print(index[i] + " "+  score[i]);
			System.out.println();
		}
	}
}

My output

2
Input 1 2
Input 3 4
Output 1 4
Output 3 2

**chaarmann** · Sep 26 '17, 11:08 AM

You need to swap the indexes also when you swap the scores in your sorting.
So add following lines after line 20:

Code:

int t = score[j];
score[j] = score[i];
score[i] = t;

By the way, professionals use objects to keep the data together. What if someone needs to add a name for each item? If you do it as a third array: Does he really think of modifying the code everywhere where the array content is swapped? Like you sorted the score but forgot to sort the corresponding index? So better is that:

Code:

public class Item {
  private int index;
  private int score;
  public Item(int index, int score) {
    this.index = index;
    this.score = score;
  }
  public void print() {
    System.out.print(index + " " + score);
  }
  public int getScore() {
    return score;
  }
}

Now you only have a single array of "items" instead 2 independent arrays that hold your data.

Code:

Item [] data= new Item[n];

It's up to you for exercise to use it in your program.
If you have problems doing so, come back to me.

Array input

Array input

Comment

Comment

Comment