Promise.all([]) doesn't work for some reason? This is odd

This follows the spec word for word. There is a slight difference in timing between Promise.all([]) and Promise.all([Promise.resolve()]).

both of these resolve with '1'

Promise.race([
    Promise.all([]).then(() => '1'),
    Promise.all([Promise.resolve()]).then('2')
])

Promise.race([
    Promise.all([Promise.resolve()]).then('2'),
    Promise.all([]).then(() => '1'),
])

1. Let promisesList be an empty list.
2. For each handler of event's navigation handler list:
   1. Append the result of invoking handler with an empty arguments list to promisesList.
3. If promisesList's size is 0, then set promisesList to « a promise resolved with undefined ».

There is a subtle timing difference between how waiting for all schedules its success and failure steps when given zero promises versus ≥1 promises. For most uses of waiting for all, this does not matter. However, with this API, there are so many events and promise handlers which could fire around the same time that the difference is pretty easily observable: it can cause the event/promise handler sequence to vary. (Some of the events and promises involved include: navigatesuccess / navigateerror, currententrychange, dispose, apiMethodTracker's promises, and the navigation.transition.finished promise.)