Martingale Convergence

I continue the theme of explaining important bookwork from the Part III course, Advanced Probability, as succinctly as possible. In this post, we consider the convergence properties of discrete time martingales.

1) Theorem: Assume X is a martingale bounded in L^1. Then

X_n\rightarrow X_\infty\in L^1(\mathcal{F}_\infty) a.s.

Remark: The theorem and proof works equally well for X a supermartingale.

Proof: Essentially, we want to reduce convergence of the random variables which make up the martingale to a countable collection of events. We do this by considering upcrossings, which counts the number of times the process alternates from less than a given interval to greater than a given interval. The formal definition will be too wide for this format, so we summarise as

N_n([a,b],X)= the number of disjoint time intervals up to time n in which X goes from [-\infty a) to (b,\infty]. Define N([a,b],X) to be the limit as n increases to infinity.

It is a genuinely easy check that a sequence converges (possibly to \infty) iff this number of upcrossings of any interval with rational bounds is finite. We will show that the martingale almost surely has this property. The key lemma is a bound due to Doob:

Lemma: (b-a)\mathbb{E}[N_n([a,b],X)]\leq \mathbb{E}[(X_n-a)^-]

 Proof: Say S_1<T_1<S_2<T_2,\ldots are the successive hitting times of [-\infty,a),(b,\infty] respectively. So N_n=\inf\{k:T_k\leq n\}. We decompose, abbreviating the number of upcrossings as N.

\sum_{k=1}^n(X_{T_k\wedge n}-X_{S_k\wedge n})=\sum_{k=1}^N(X_{T_k}-X_{S_k})+(X_n-X_{S_{N+1}})1_{\{S_{N+1}\leq n\}}

Now take an expectation of both sides, applying the Optional Stopping Theorem to the bounded stopping times on the LHS. (If we are working with a supermartingale, formally we need to take \mathbb{E}[\cdot|\mathcal{F}_{S_k}] of each summand on LHS to show that they are non-negative, and so taking a further expectation over \mathcal{F}_{S_k} gives the required result.) We obtain:

0\geq (b-a)\mathbb{E}N-\mathbb{E}(X_n-X_{S_{N+1}})1_{\{S_{N+1}\leq n\}}

If S_{N+1}>n then both 1_{\{S_{N+1}\leq n\}}=(X_n-a)^-=0. Otherwise (X_n-a)^-\geq X_{S_{N+1}}-X_n. This complete the proof of the lemma.

Since \mathbb{E}[(X_n-a)^-]\leq \mathbb{E}|X_n|+a<\infty, where this last bound is uniform in by assumption, applying monotone convergence, we get that N([a,b],X) is almost surely finite for every pair a<b\in\mathbb{Q}. Because this set is countable, we can deduce that this holds almost surely for every pair simultaneously. We therefore define X_\infty(w)=\lim X_n(w) when this limit exists, and 0 otherwise. With probability one the limit exists. Fatou’s lemma confirms that X_\infty\in L^1(\mathcal{F}_\infty).

2) We often want to have convergence in L^1 as well. Recall for Part II Probability and Measure (or elsewhere) that

UI + Convergence almost surely is necessary and sufficient for convergence in L^1.

This applies equally well to this situation. Note that for a martingale, this condition is often convenient, because, for example, we know that the set \{\mathbb{E}[X_\infty|\mathcal{F}_n],n\} is UI for any integrable X_\infty.

3) Convergence in L^p is easier to guarantee.

Theorem: i) X a martingale bounded in L^p iff ii) X_n\rightarrow X_\infty in L^p and almost surely iff iii) \exists Z\in L^p s.t. X_n=\mathbb{E}[Z|\mathcal{F}_n] a.s.

Remark: As part of the proof, we will show, as expected, that X_\infty,Z are the same.

Proof: i)->ii) Almost sure convergence follows from the above result applied to the p-th power process. We apply Doob’s inequality about running maxima in a martingale process:

||X_n^*||_p:=||\sup_{m\leq n}X_m||_p\leq \frac{p}{p-1}||X_n||_p

Using this, we see that X_n^*\uparrow X_\infty^*:=\sup|X_k|. Now consider |X_n-X_\infty|\leq 2X_\infty^*\in L^p and use Dominated Convergence to confirm convergence in L^p.

Note that Doob’s L^p inequality can be proven using the same author’s Maximal inequality and Holder.

ii)->iii) As we suspected, we show Z=X_\infty is suitable.

||X_n-\mathbb{E}[X_\infty|\mathcal{F}_n]||_p\stackrel{\text{large }m}{=}||\mathbb{E}[X_m-X_\infty|\mathcal{F}_n]||_p\stackrel{\text{Jensen}}{\leq}||X_m-X_\infty||_p\rightarrow 0

iii)->i) is easy. Z bounded in L^p implies X bounded by a simple application of the triangle inequality in the definition of conditional expectation.

Convergence of Random Variables

The relationship between the different modes of convergence of random variables is one of the more important topics in any introduction to probability theory. For some reason, many of the textbooks leave the proofs as exercises, so it seems worthwhile to present a sketched but comprehensive summary.

Almost sure convergence: X_n\rightarrow X\;\mathbb{P}-a.s. if \mathbb{P}(X_n\rightarrow X)=1.

Convergence in Probability: X_n\rightarrow X in \mathbb{P}-probability if \mathbb{P}(|X_n-X|>\epsilon)\rightarrow 0 for any \epsilon>0.

Convergence in Distribution: X_n\stackrel{d}{\rightarrow} X if \mathbb{E}f(X_n)\rightarrow \mathbb{E}f(X) for any bounded, continuous function f. Note that this definition is valid for RVs defined on any metric space. When they are real-valued, this is equivalent to the condition that F_{X_n}(x)\rightarrow F_X(x) for every point x\in \mathbb{R} where F_X is continuous. It is further equivalent (by Levy’s Convergence Theorem) to its own special case, convergence of characteristic functions: \phi_{X_n}(u)\rightarrow \phi_X(U) for all u\in\mathbb{R}.

Note: In contrast to the other conditions for convergence, convergence in distribution (also known as weak convergence) doesn’t require the RVs to be defined on the same probability space. This thought can be useful when constructing counterexamples.

L^p-convergence: X_n\rightarrow X in L^p if ||X_n-X||_p\rightarrow 0; that is, \mathbb{E}|X_n-X|^p\rightarrow 0.

Uniform Integrability: Informally, a set of RVs is UI if the integrals over small sets tend to zero uniformly. Formally: (X_n) is UI if \sup_{n,A\in\mathcal{F}}\{\mathbb{E}[|X_n|1(A)]|\mathbb{P}(A)\leq \delta\}\rightarrow 0 as \delta\rightarrow 0.

Note: In particular, a single RV, and a collection of independent RVs are UI. If X~U[0,1] and X_n=n1(X\leq \frac{1}{n}), then the collection is not UI.

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