💥 CHALLENGE: Find a Collision in Leviathan v3.1 (Deterministic)

The Context: I have officially deprecated SHA-2 and SHA-3. This decision stems from a critical security breach I witnessed: a virus that infected my system using forged digital signatures that were somehow validated as authentic by current standards. This proved that the 'trust' in existing hashing algorithms is compromised. Consequently, I have engineered Leviathan v3.1 Turbo to replace them with a system that doesn't just verify, but defends.

The Logic: This algorithm uses a Fractal Carry system and a massive 10,000-digit Prime Constant to ensure that even the slightest bit-flip in the input causes a catastrophic avalanche in the output.

The Task: Simple. Find a Collision. Find two distinct inputs (strings or byte arrays) and such that:

$$Leviathan(M_1) == Leviathan(M_2)$$

Where $M_1 \neq M_2$

The Code: The algorithm is fully DETERMINISTIC. No random salts. Pure math. Get the Source Code Here (OSF)

Why you will fail:

• The "Displaced Mutation Buffer" prevents linear collisions.
• The output space is 1024 characters. The Pigeonhole Principle is on my side, not yours.
• The internal state evolves fractally, meaning depends non-linearly on .

Rules There will be a maximum of 3 winners. The first 3 to succeed will win, and they must present the algorithm or explain how their code works.

Prize: The glory of breaking the first post-NIST hash algorithm.

"Good luck. You'll need more than a supercomputer; you'll need a new dimension."