Bytes to Segfault
Challenge
Cause the currently running program to receive the SIGSEGV signal (on Linux or other *nix systems) as fast as possible. What it does with the signal doesn't matter as long as it receives it.
This is code golf, smallest answer in each language wins. Some languages will have a tougher time than others. Keep in mind that if you depend on uninitalized data, it needs to always result in a segfault; a 0.000001% chance to not work invalidates your solution.
Example program
#include <stddef.h>
#include <stdio.h>
int main() {
int* ohno = NULL;
printf("%d", *ohno);
}
C, 5 bytes ```c main; ``` …
5y ago
[Python 2], 13 bytes …
5y ago
[Bash], 11 kill -11 …
5y ago
Rust 1.0.0, 58 53 52 37 bytes …
5y ago
x86 machine code, 3 bytes …
9mo ago
[JavaScript (Node.js)], 35 32 …
5y ago
C, 16 bytes ```c m(){(int)m= …
5y ago
Ruby, 14 bytes ```ruby `ki …
4y ago
C (compliant), 19 bytes (`g …
5y ago
Python, 123 bytes I'm just …
6mo ago
[Rust], 47 bytes fn …
4y ago
Swift 5.4, 17 bytes ``` fu …
4y ago
12 answers
C, 5 bytes
main;
This exploits the fact that uninitialised globals live in the .bss section, and that section is not executable. So any attempt to execute code there, regardless of content, will cause a segfault.
C, 16 bytes
m(){*(int*)m=0;}
x86 machine code, 3 bytes
31 FF AB
In assembly:
xor edi, edi
stosd
Set EDI to 0 by XORing it with itself, then use the 1-byte stosd instruction to try to write EAX to that address while advancing EDI.
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Python, 123 bytes
I'm just happy I got python to segfault :) there must be a better way to golf this.
a=lambda:0;e=tuple()
b=type(a.__code__)(0,0,0,0,0,0,(lambda x:x).__code__.co_code,e,e,e,'','','',0,b'',b'')
type(a)(b,{})()
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Swift 5.4, 17 bytes
func f(){f()};f()
Pretty simple. It just calls itself until it stack overflows. You need to compile and run it, not just do it in the REPL, because the REPL just drops you back into the interpreter once it overflows.
It gives a warning "all paths through this function will call itself", but eh who cares?
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