π―ππΊπππΊππβ κ°β π
β κ«Χ
Β .β πβ π π
π
πππππ ππΊπππ π
πΊπ½ππ
πππΎ ππ ππΎπ
ππΎππ, βππΎππΎ.
π½πππ§ππ π’πππ£πππ π
Joined March 2013
@joohyfn hasnβt posted
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