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Java Articles
Page 78 of 450
Difference between TreeMap, HashMap and LinkedHashMap in Java programming
HashMap, TreeMap and LinkedHashMap all implements java.util.Map interface and following are their characteristics.HashMapHashMap has complexity of O(1) for insertion and lookup.HashMap allows one null key and multiple null values.HashMap does not maintain any order.TreeMapTreeMap has complexity of O(logN) for insertion and lookup.TreeMap does not allow null key but allow multiple null values.TreeMap maintains order. It stores keys in sorted and ascending order.LinkedHashMapLinkedHashMap has complexity of O(1) for insertion and lookup.LinkedHashMap allows one null key and multiple null values.LinkedHashMap maintains order in which key-value pairs are inserted.Exampleimport java.util.HashMap; import java.util.Hashtable; import java.util.LinkedHashMap; import java.util.Map; import java.util.TreeMap; public class Tester { ...
Read MoreDifference between x++ and x= x+1 in Java programming
x++ automatically handles the type casting where as x= x + 1 needs typecasting in case of x is not an int variable. See the example below.Examplepublic class Tester { public static void main(String args[]) { byte b = 2; //Type casting is required //as 1 is int and b is byte variable b = (byte) (b + 1); System.out.println(b); byte b1 = 2; //Implcit type casting by the compiler b1++; System.out.println(b1); } }Output3 3
Read MoreFibonacci of large number in java
Fibonacci numbers of Fibonacci series grows exponentially and can be very large for large numbers like 500 or 1000. To handle such number, long data type is not sufficient. BigInteger can handle large number easily. BigInteger is useful in scenarios where calculations results in data which is out of limit for available primitive data types. See the example below of getting Fibonacci number of 100 and 1000.Exampleimport java.math.BigInteger; public class Tester { public static void main(String args[]) { System.out.println("Fibonacci of 100: "); System.out.println(fibonacci(100)); System.out.println("Fibonacci of 1000: "); ...
Read MoreFind frequency of each word in a string in Java
In order to get frequency of each in a string in Java we will take help of hash map collection of Java.First convert string to a character array so that it become easy to access each character of string.Now compare for each character that whether it is present in hash map or not in case it is not present than simply add it to hash map as key and assign one as its value.And if character is present than find its value which is count of occurrence of this character in the string (initial we put as 1 when it ...
Read MoreDisplay the minimum and maximum value of primitive data types in Java
Every data type in Java has a minimum as well as maximum range, for example, for Float.Min = 1.4E-45 Max = 3.4028235E38Let’s say for Float, if the value extends the maximum range displayed above, it leads to Overflow.However, if the value is less than the minimum range displayed above, it leads to Underflow.The following is the Java Program to display the minimum and maximum value of primitive data types.Examplepublic class Demo { public static void main(String[] args) { System.out.println("Integer Datatype values..."); System.out.println("Min = " + Integer.MIN_VALUE); System.out.println("Max = " + ...
Read MoreOverflow of DataTypes in Java
Overflow occurs when the given value is more than the maximum prescribed size of a data type. The overflow condition can result to an error or now the implementation of the programming language handles it on its own.To display overflow of datatypes, I have taken an example of float datatype. Float data type is a single-precision 32-bit IEEE 754 floating point.The range of a float datatype is −approximately ±3.40282347E+38FThe following program display overflow of datatypes in Java.Examplepublic class Demo { public static void main(String[] args) { System.out.println("Displaying Overflow... "); float val1 = 3.3976835E38f; ...
Read MoreBoolean Type in Java
To display Boolean type, firstly take two variables and declare them as boolean.boolean val1, val2;Then one by one assign values to both of them, one of them is shown below −val1 = true;Now, use if statement to check and display the Boolean true value.if(val1) System.out.println("This is true and will get displayed!");Let us now see the complete example to work with Boolean Type in Java.Examplepublic class Demo { public static void main(String[] args) { boolean val1, val2; System.out.println("Boolean Type in Java"); val1 = true; if(val1) ...
Read MoreJava Program to convert an int to a boolean specifying the conversion values
To convert int to boolean, let us first take the following int.int one = 1; int two = 1; int three = 0;We have nested if-else statement to display the true or false values. Here, the value “one” is the same as “two” i.e. 1; therefore, the following works −else if (one.equals(two)) { System.out.println(true); }The above display “true” and in this way we converted int to boolean.Let us now see the complete example to learn how to convert int to Boolean.Examplepublic class Demo { public static void main(String[] args) { int one = 1; ...
Read MoreJava Program to check for Integer overflow
To check for Integer overflow, we need to check the Integer.MAX_VALUE, which is the maximum value of an integer in Java.Let us see an example wherein integers are added and if the sum is more than the Integer.MAX_VALUE, then an exception is thrown.Examplepublic class Demo { public static void main(String[] args) { int val1 = 9898989; int val2 = 6789054; System.out.println("Value1: "+val1); System.out.println("Value2: "+val2); long sum = (long)val1 + (long)val2; if (sum > Integer.MAX_VALUE) { throw new ...
Read MoreDisplay the maximum of three integer values in Java
The following is an example displaying the maximum of three integer values.Examplepublic class Demo { public static void main(String[] args) { int val1 = 10; int val2 = 20; int val3 = 30; System.out.println("Number 1 = "+val1); System.out.println("Number 2 = "+val2); System.out.println("Number 3 = "+val3); if (val2 > val1) { val1 = val2; } if (val3 > val1) { val1 = val3; ...
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