Article Categories
- All Categories
-
Data Structure
-
Networking
-
RDBMS
-
Operating System
-
Java
-
MS Excel
-
iOS
-
HTML
-
CSS
-
Android
-
Python
-
C Programming
-
C++
-
C#
-
MongoDB
-
MySQL
-
Javascript
-
PHP
Java Articles
Page 24 of 450
Character class: subtraction - Java regular expressions
You can subtract one range from other and use it as new range. You can achieve this by using two variants of character classes i.e. negation and intersection.For example the intersection of ranges [a-l] and [^e-h] gives you the characters a to l as rage subtracting the characters [e-h]Exampleimport java.util.Scanner; import java.util.regex.Matcher; import java.util.regex.Pattern; public class RegexExample1 { public static void main(String[] args) { Scanner sc = new Scanner(System.in); System.out.println("Enter input text: "); String input = sc.nextLine(); String regex = "[a-l&&[^e-h]]"; //Creating a pattern ...
Read MoreRegular Expression Q Metacharacter in Java
The subexpression/metacharacter "\Q" escapes all characters up to "\E" i.e. you can escape metacharacters in the regular expressions by placing them in between \Q and \E. For example, the expression [aeiou] matches the strings with vowel letters in it.Example import java.util.Scanner; import java.util.regex.Matcher; import java.util.regex.Pattern; public class SampleProgram { public static void main( String args[] ) { String regex = "[aeiou]"; Scanner sc = new Scanner(System.in); System.out.println("Enter input string: "); String input = sc.nextLine(); //Creating a Pattern object Pattern pattern = Pattern.compile(regex); ...
Read MoreJava program to remove all numbers in a string except "1" and "2"?
The regular expression "(?digit(?!\d)" matches the digit specified.The replaceAll() method accepts two strings: a regular expression pattern and, the replacement string and replaces the pattern with the specified string.Therefore, to remove all numbers in a string except 1 and 2, replace the regular expressions 1 and 2 with one and two respectively and replace all the other digits with an empty string.Exampleimport java.util.Scanner; public class RegexExample { public static void main(String args[]) { //Reading String from user System.out.println("Enter a String"); Scanner sc = new Scanner(System.in); String input ...
Read MoreJava regex program to match parenthesis "(" or, ")".
Following regular expression accepts a string with parenthesis −"^.*[\(\)].*$";^ matches the starting of the sentence..* Matches zero or more (any) characters.[\(\)] matching parenthesis.$ indicates the end of the sentence.Example 1import java.util.Scanner; import java.util.regex.Matcher; import java.util.regex.Pattern; public class SampleTest { public static void main( String args[] ) { String regex = "^.*[\(\)].*$"; //Reading input from user Scanner sc = new Scanner(System.in); System.out.println("Enter data: "); String input = sc.nextLine(); //Instantiating the Pattern class Pattern pattern = Pattern.compile(regex); ...
Read MoreCounting the number of groups Java regular expression
You can treat multiple characters as a single unit by capturing them as groups. You just need to place these characters inside a set of parentheses.You can count the number of groups in the current match using the groupCount() method of the Matcher class. This method calculates the number of capturing groups in the current match and returns it.Exampleimport java.util.regex.Matcher; import java.util.regex.Pattern; public class Test { public static void main(String[] args) { String str1 = "This is an example HTML script where ever alternative word is bold."; //Regular expression to match contents of ...
Read MoreRegular expression “[X?+] ” Metacharacter Java
The Possessive Quantifier [X?+] matches the X present once or not present at all.Examplepackage com.tutorialspoint; import java.util.regex.Matcher; import java.util.regex.Pattern; public class PossesiveQuantifierDemo { private static final String REGEX = "T?+"; private static final String INPUT = "abcdTatW"; public static void main(String[] args) { // create a pattern Pattern pattern = Pattern.compile(REGEX); // get a matcher object Matcher matcher = pattern.matcher(INPUT); while(matcher.find()) { //Prints the start index of the match. System.out.println("Match String start(): "+matcher.start()); ...
Read MoreNon capturing groups Java regular expressions:
Using capturing groups you can treat multiple characters as a single unit. You just need to place the characters to be grouped inside a set of parentheses. For example −(.*)(\d+)(.*)If you are trying to match multiple groups the match results of each group is captured. You can get the results a group by passing its respective group number to the group() method. 1, 2, 3 etc.. (from right to left) group 0 indicates the whole match.Exampleimport java.util.Scanner; import java.util.regex.Matcher; import java.util.regex.Pattern; public class CapturingGroups { public static void main( String args[] ) { System.out.println("Enter input text"); ...
Read MoreGetting the list of all the matches Java regular expressions
Java does not provide any method to retrieve the list of all matches we need to use Lists and add the results to it in the while loop.Exampleimport java.util.ArrayList; import java.util.Iterator; import java.util.Scanner; import java.util.regex.Matcher; import java.util.regex.Pattern; public class ListOfMatches{ public static void main(String[] args) { Scanner sc = new Scanner(System.in); System.out.println("Enter input text: "); String input = sc.nextLine(); String regex = "\d+"; //Creating a pattern object Pattern pattern = Pattern.compile(regex); ArrayList list = new ArrayList(); ...
Read MoreFinding a Match Within Another Match Java regular expressions
To match a pattern within another match you need to compile the regular expression to match the outer pattern find the match retrieve the results and pass the results as input to the inner Matcher object.Exampleimport java.util.Scanner; import java.util.regex.Matcher; import java.util.regex.Pattern; public class MatcherExample { public static void main(String[] args) { int start = 0, len = -1; Scanner sc = new Scanner(System.in); System.out.println("Enter input text: "); String input = sc.nextLine(); String regexOuter = "(.*?)"; String regexInner = "\d+"; ...
Read MoreReplacing all the matched contents Java regular expressions
Once you compile the required regular expression and retrieved the matcher object by passing the input string as a parameter to the matcher() method.You can replace all the matched parts of the input string with another str4ing using the replaceAll() method of the Matcher class.This method accepts a string (replacement string) and replaces all the matches in the input string with it and returns the result.Example 1import java.util.Scanner; import java.util.regex.Matcher; import java.util.regex.Pattern; public class ReplaceAll{ public static void main(String[] args) { Scanner sc = new Scanner(System.in); System.out.println("Enter input text: "); ...
Read More