Regular Expression "^" (caret) Metacharacter in Java

The subexpression/metacharacter “^” matches the beginning of a line. If you use this in a regular expression, it matches the sentence succeeding it in the input string.

Example 1

import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class RegexExample {
   public static void main( String args[] ) {
      String regex = "^Hi how are you";
      String input = "Hi how are you welcome to Tutorialspoint";
      Pattern p = Pattern.compile(regex);
      Matcher m = p.matcher(input);
      int count = 0;
      while(m.find()) {
         count++;
      }
      System.out.println("Number of matches: "+count);
   }
}

Output

Number of matches: 1

Example 2

The following Java program accepts 5 strings from the user and prints the strings starting with a digit.

import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class StartingwithDigit {
   public static void main( String args[] ) {
      String regex = "^[0-9].*$";
      Scanner sc = new Scanner(System.in);
      System.out.println("Enter 5 input strings: ");
      String input[] = new String[5]; Regular expressions - Answers
      for (int i=0; i
Output
Enter 5 input strings:
sample string 1
sample string 2
11 sample string 3
22 sample string 4
43534 56353 636
Strings starting with digits:
11 sample string 3
22 sample string 4
43534 56353 636