C++ program to Reverse a Number

Write a C++ program to Reverse a Number with an example. In this reverse number example, the while loop checks whether the given value is greater than 0.

• reminder = number%10 – It gives the last digit
• reverse = reverse * 10 + reminder – It adds that last digit at the first position. Because of reverse * 10, the value will add at the 2nd, 3rd,…nth positions. Otherwise, it replaces the existing ones.
• number= number/10 – it removes the last digit from it.

#include<iostream>

using namespace std;

int main()
{
	int number, reminder, reverse = 0;
	
	cout << "Please Enter the Number that you want to Reverse  =  ";
	cin >> number;
	
	while (number > 0)
	{
    	reminder = number % 10;
    	reverse = reverse * 10 + reminder;
    	number = number / 10;
	}
	cout << "\nReverse of given Number = " << reverse;
		
 	return 0;
}

C++ program to Reverse a Number using For Loop

#include<iostream>

using namespace std;

int main()
{
	int number, reminder, reverse = 0;
	
	cout << "Please Enter the Num  =  ";
	cin >> number;
	
	for (;number > 0; number = number / 10)
	{
    	reminder = number % 10;
    	reverse = reverse * 10 + reminder;
	}
	cout << "\nReverse of given Num = " << reverse;
		
 	return 0;
}

Please Enter the Num  =  67859

Reverse of given Num = 95876

This code helps to Reverse a Number using a Recursive Function.

#include<iostream>
using namespace std;

int reverseNumber(int number)
{
	static int reminder, reverse = 0;
	
	if (number > 0)
	{
    	reminder = number % 10;
    	reverse = reverse * 10 + reminder;
    	reverseNumber(number / 10);
	}
	
	return reverse;
	
}
int main()
{
	int num, rev = 0;
	
	cout << "Please Enter the Num  =  ";
	cin >> num;
	
	rev = reverseNumber(num);
	cout << "\nReverse of given = " << rev;
		
 	return 0;
}

Please Enter the Num  =  478956

Reverse of given = 659874