Q. Can you write code to identify missing numbers in a given array of numbers?
Solution 1: Assuming that the given numbers are in order
Finding the missing number
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public class MissingNumber { public static void main(String[] args) { int numbers[] = { 2, 3, 4, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 18 }; new MissingNumber().findMissingNumbers(numbers, 0, 20); } private void findMissingNumbers(int[] input, int first, int last) { printMissingNumbersFront(input, first); printMissingNumbersInTheMiddle(input, last); printMissingNumbersBack(input, last); } /** * before 2 * @param input * @param first */ private void printMissingNumbersFront(int[] input, int first) { //0 and 1 are less than 2 as per the above input for (int i = first; i < input[0]; i++) { System.out.println(i); } } /** * after 18 * @param input * @param last */ private void printMissingNumbersBack(int[] input, int last) { // 1 + the last element value is 19. 19 to 20 are less than or equal to the last value of 20 for (int i = 1 + input[input.length - 1]; i <= last; i++) { System.out.println(i); } } /** * between 2 and 18 * @param input * @param last */ private void printMissingNumbersInTheMiddle(int[] input, int last) { //for a given index i, index [i-1]+1 should be equal if present. for (int i = 1; i < input.length; i++) { //e.g. for input[1] = 3, j=1+2 //input[2] = 4, j=1+3 //input[3] = 6, j=4+1, Oops 5 is less than 6 so print //input[4] = 7, j=6+1 //if index[i] < index[i-1] + 1, then number index[i-1] + 1 is missing for (int j = 1+input[i-1]; j < input[i]; j++) { System.out.println(j); } } } } |
Output:
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1 2 3 4 5 6 7 |
0 1 5 16 17 19 20 |
The above solution assumes that the numbers are in order (i.e. sorted). What if the numbers are random?
Solution 2: Numbers are added randomly.
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import java.util.Set; import java.util.concurrent.CopyOnWriteArraySet; public class MissingNumber { public static void main(String[] args) { int numbers[] = { 7, 3, 6, 4, 2, 8, 9, 10, 12, 14, 13, 11, 15, 18 }; new MissingNumber().findMissingNumbers(numbers, 0, 20); } private void findMissingNumbers(int[] input, int first, int last) { Set<Integer> expectedNumbers = new CopyOnWriteArraySet<Integer>(); for (int i = first; i <= last; i++) { expectedNumbers.add(i); } //remove numbers from the above set that are in the input. for (int i = 0; i < input.length; i++) { if(expectedNumbers.contains(input[i])) { expectedNumbers.remove(input[i]); //CopyOnWriteArraySet is used that //You won't get ConcurrentModificationException } } //left over numbers in the set are the missing numbers for (Integer number : expectedNumbers){ System.out.println(number); } } } |
Output:
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1 2 3 4 5 6 7 |
0 1 5 16 17 19 20 |
