The java.lang.StrictMath.floor() is the inbuilt method which returns the largest double value, less than or equal to the given argument and is equal to the integer value.
- The result is the same as the argument when the given argument is equal to the integer.
- The result is the same as the argument when the given argument is NaN, infinity, positive zero or negative zero.
Syntax :
public static double floor(double num)
Parameters: This method accepts one parameter num which is of double type .
Return Value : The method returns the largest value which, closest to positive infinity, less than or equal to the argument and equal to an integer.
Examples :
Input: num = 9.6 Output: 9.0 Input: num = -7.8 Output: -8.0
Below programs illustrate the java.lang.StrictMath.floor() method:
Program 1:
// Java program to illustrate the
//java.lang.StrictMath.floor()
import java.lang.*;
public class Geeks {
public static void main(String[] args) {
double num1 = 7.8, num2 = 1.4 ;
double fValue = StrictMath.floor(num1);
System.out.println("The floor value of "+
num1+" = " + fValue);
fValue = StrictMath.floor(num2);
System.out.println("The floor value of "+
num2+" = " + fValue);
}
}
Output:
The floor value of 7.8 = 7.0 The floor value of 1.4 = 1.0
Program2:
// Java program to illustrate the
//java.lang.StrictMath.floor()
import java.lang.*;
public class Geeks {
public static void main(String[] args) {
double num1 = -7.8, num2 = -1.4 ,num3 = 0.1 ;
double fValue = StrictMath.floor(num1);
System.out.println("The floor value of "+
num1+" = " + fValue);
fValue = StrictMath.floor(num2);
System.out.println("The floor value of "+
num2+" = " + fValue);
fValue = StrictMath.floor(num3);
System.out.println("The floor value of "+
num3+" = " + fValue);
}
}
Output:
The floor value of -7.8 = -8.0 The floor value of -1.4 = -2.0 The floor value of 0.1 = 0.0