SQLite Describe Table

Summary: in this tutorial, you will learn about various ways to show the structure of a table in SQLite.

Getting the structure of a table via the SQLite command-line shell program

To find out the structure of a table via the SQLite command-line shell program, you follow these steps:

First, connect to a database via the SQLite command-line shell program:

sqlite3 c:\sqlite\db\chinook.db
Code language: SQL (Structured Query Language) (sql)

Then, issue the following command:

.schema table_name
Code language: SQL (Structured Query Language) (sql)

For example, the following command shows the statement that created the albums table:

.schema albums
Code language: SQL (Structured Query Language) (sql)

Notice that there is no semicolon (;) after the table name. If you add a semicolon (;), the .schema will consider the albums; as the table name and returns nothing because the table albums; does not exist.

Here is the output:

CREATE TABLE IF NOT EXISTS "albums" ( [AlbumId] INTEGER PRIMARY KEY AUTOINCREMENT NOT NULL, [Title] NVARCHAR(160) NOT NULL, [ArtistId] INTEGER NOT NULL, FOREIGN KEY ([ArtistId]) REFERENCES "artists" ([ArtistId]) ON DELETE NO ACTION ON UPDATE NO ACTION ); CREATE INDEX [IFK_AlbumArtistId] ON "albums" ([ArtistId]);
Code language: SQL (Structured Query Language) (sql)

Another way to show the structure of a table is to use the PRAGMA command. To do it, you use the following command to format the output:

.header on .mode column
Code language: SQL (Structured Query Language) (sql)

And use the PRAGMA command as follows:

pragma table_info('albums');
Code language: JavaScript (javascript)

The following picture shows the output:

cid name type notnull dflt_value pk --- -------- ------------- ------- ---------- -- 0 AlbumId INTEGER 1 1 1 Title NVARCHAR(160) 1 0 2 ArtistId INTEGER 1 0

Getting the structure of a table using the SQL statement

You can find the structure of a table by querying it from the sqlite_schema table as follows:

SELECT sql FROM sqlite_schema WHERE name = 'albums';
Code language: SQL (Structured Query Language) (sql)

Here is the output:

sql ------------ CREATE TABLE "albums" ( [AlbumId] INTEGER PRIMARY KEY AUTOINCREMENT NOT NULL, [Title] NVARCHAR(160) NOT NULL, [ArtistId] INTEGER NOT NULL, FOREIGN KEY ([ArtistId]) REFERENCES "artists" ([ArtistId]) ON DELETE NO ACTION ON UPDATE NO ACTION )
Code language: SQL (Structured Query Language) (sql)

In this tutorial, you have learned how to show the structure of a table in SQLite via a command-line shell program or SQL statement.

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