Python Numpy Linspace function for bidimensional array

Question

I know it is possible to create numpy arrays using the Linspace function. For example, given a range [x,y] I can make a vector of z elements equally distanced in [x,y]

v = np.linspace(x, y, z, retstep=True)

What if one needs more dimensions? Is it possible to use the same function to generate a 3x4 array? I tried by creating simple arrays and then merge them, but I don't think that is an efficient way to do that

linspace lets you use arrays for x and y. It in effect makes the z element array, and scales to fit between the matching x and y values. — hpaulj
– hpaulj, Commented Mar 15, 2021 at 18:47

FearoftheDark · Accepted Answer · 2021-03-15 20:33:09Z

0

You can use arrays for start and stop point of linspace:

x=np.linspace((0,0,0), (3,5,14), 4, axis=1)
print(x)

This will give the output:

[[ 0.          1.          2.          3.        ]
 [ 0.          1.66666667  3.33333333  5.        ]
 [ 0.          4.66666667  9.33333333 14.        ]]

answered Mar 15, 2021 at 20:33

FearoftheDark

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