I wrote code like this:
print re.findall(r'(<td width="[0-9]+[%]?" align="(.+)">|<td align="(.+)"> width="[0-9]+[%]?")([ \n\t\r]*)([0-9,]+\.[0-9]+)([ \n\t\r]*)([&]?[a-zA-Z]+[;]?)([ \n\t\r]*)<span class="(.+)">',r.text,re.MULTILINE)
to get this line:
<td width="47%" align="left">556.348 <span class="uccResCde">
I want the value 556.348. How I can get it using regular expressions?
A straight cut and paste from the HTMLParser documentation will get you the data out of the tags, but not using regular expressions.
from HTMLParser import HTMLParser
# Create a subclass and override the handler methods
class MyHTMLParser(HTMLParser):
def handle_starttag(self, tag, attrs):
print "Encountered a start tag:", tag
def handle_endtag(self, tag):
print "Encountered an end tag :", tag
def handle_data(self, data):
print "Encountered some data :", data
# Instantiate the parser and fed it some HTML
parser = MyHTMLParser()
parser.feed('<td width="47%" align="left">556.348 <span class="uccResCde">')
Here is a solution that should explain how to get the matched group. You should read the documentation.
import re
text_to_parse= '<td width="47%" align="left">556.348 <span class="uccResCde">'
pattern = r'(<td width="[0-9]+[%]?" align="(.+)">|<td align="(.+)"> width="[0-9]+[%]?")([ \n\t\r]*)([0-9,]+\.[0-9]+)([ \n\t\r]*)([&]?[a-zA-Z]+[;]?)([ \n\t\r]*)<span class="(.+)">'
m = re.search(pattern, text_to_parse)
m.group(5)
But in order to parse HTML one should not need to use regular expressions. Instead, use an HTML parser, such as Beautiful Soup:
from bs4 import BeautifulSoup
soup = BeautifulSoup(text_to_parse)
soup.text
