Each expression in C++11 has a value category. One of lvalue, xvalue or prvalue.
Is there a way to write a macro that, given any expression as an argument, will produce a string "lvalue", "xvalue" or "prvalue" as appropriate?
For example:
int main()
{
int x;
cout << VALUE_CAT(x) << endl; // prints lvalue
cout << VALUE_CAT(move(x)) << endl; // prints xvalue
cout << VALUE_CAT(42) << endl; // prints prvalue
}
How could VALUE_CAT be implemented?
decltype can return the declared type of an entity (hence the name), but can also be used to query the type of an expression. However, in the latter case the resulting type is 'adjusted' according to the value category of that expression: an lvalue expression results in an lvalue reference type, an xvalue in an rvalue reference type, and a prvalue in just the type. We can use this to our benefit:
template<typename T>
struct value_category {
// Or can be an integral or enum value
static constexpr auto value = "prvalue";
};
template<typename T>
struct value_category<T&> {
static constexpr auto value = "lvalue";
};
template<typename T>
struct value_category<T&&> {
static constexpr auto value = "xvalue";
};
// Double parens for ensuring we inspect an expression,
// not an entity
#define VALUE_CATEGORY(expr) value_category<decltype((expr))>::value
decltype "mapped" expression value categories (lvalue, xvalue, prvalue) to reference types (lvalue reference to T, rvalue reference to T, T). Thanks.
decltype with the expression wrapped in double-parenthesis like that. That changes how decltype deduces the expression's type.decltype(...) is documented in N3485 7.1.6.2/4id-expression. For example decltype(move(x)) will produce int&& as expected.
#ifndef _TPF_TYPE_NAME_H
#define _TPF_TYPE_NAME_H
template <typename T>
constexpr bool is_lvalue_helper = std::is_lvalue_reference<T>::value;
template <typename T>
constexpr bool is_xvalue_helper = std::is_rvalue_reference<T>::value;
template <typename T>
constexpr bool is_prvalue_helper = !(is_lvalue_helper<T> || is_xvalue_helper<T>);
template <typename T>
constexpr bool is_rvalue_helper = is_xvalue_helper<T> || is_prvalue_helper<T>;
template <typename T>
constexpr bool is_glvalue_helper = is_xvalue_helper<T> || is_lvalue_helper<T>;
#define is_lvalue(type_instance) is_lvalue_helper<decltype((type_instance))>
#define is_xvalue(type_instance) is_xvalue_helper<decltype((type_instance))>
#define is_prvalue(type_instance)is_prvalue_helper<decltype((type_instance))>
#define is_rvalue(type_instance) is_rvalue_helper<decltype((type_instance))>
#define is_glvalue(type_instance)is_glvalue_helper<decltype((type_instance))>
#endif // end of _TPF_TYPE_NAME_H
You could also try using the clang API's Classification function to return the category of the expression from a clang AST containing the expression. This is, of course, far more complex than @Luc's solution, since it requires generating the actual AST through clang.
#define VALUE_CAT(expr) get_value_description(sizeof SFINAE_test_1((expr)), sizeof SFINAE_test_2((expr)))constexprfunctions). (Actually I'm really glad that's not the case, would make overload resolution more convoluted than it already is!)