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Python Programs to Print Patterns – Print Number, Pyramid, Star, Triangle, Diamond, and Alphabets Patterns

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This Python lesson includes over 35+ coding programs for printing Numbers, Pyramids, Stars, triangles, Diamonds, and alphabet patterns, ensuring you gain hands-on experience and confidence in your Python skills.

Printing numbers, stars (asterisk), or other characters in different shapes (patterns) is a frequently asked interview question for freshers. Creating these number and pyramid patterns allows you to test your logical ability and coding skills.

In this lesson, you’ll learn how to print patterns using the for loop, while loop, and the range() function.

This article teaches you how to print the following patterns in Python.

  • Number pattern
  • Pyramid pattern
  • Inverted pyramid pattern
  • Half pyramid pattern
  • Triangle pattern
  • Star (*) or asterisk pattern
  • Diamond Shaped pattern
  • Characters or alphabet pattern
  • Square pattern
Print Pattern in Python
Print Pattern in Python

Table of contents

Steps to Print Pattern in Python

To print any pattern, you must first understand its logic and technique. Use the below steps to print any pattern in Python.

  1. Decide the number of rows and columns

    The number of rows and columns is crucial when printing a pattern. To achieve this, we utilize two loops: outer loops and nested loops. The outer loop is the number of rows, while the inner loop tells us the column needed to print the pattern.

    The input () function accepts the number of rows from a user to decide the size of a pattern.

  2. Iterate rows

    Next, write an outer loop to Iterate the number of rows using a for loop and range() function.

  3. Iterate columns

    Next, write the inner or nested loop to handle the number of columns. The internal loop iteration depends on the values of the outer loop.

  4. Print star or number

    Use the print() function in each iteration of nested for loop to display the symbol or number of a pattern (like a star (asterisk *) or number).

  5. Add a new line after each iteration of the outer loop

    Add a new line using the print() function after each iteration of the outer loop so that the pattern displays appropriately

Algorithm for printing patterns in Python
Algorithm for printing patterns in Python

Also, Solve:

Number Patterns Programs In Python

I have created various programs that print different styles of number patterns. Let’s see them one by one. Let’s print the following number pattern using a for loop.

1  
2 2  
3 3 3  
4 4 4 4  
5 5 5 5 5

Program:

rows = 6
# if you want user to enter a number, uncomment the below line
# rows = int(input('Enter the number of rows'))
# outer loop
for i in range(rows):
    # nested loop
    for j in range(i):
        # display number
        print(i, end=' ')
    # new line after each row
    print('')Code language: Python (python)

In this number pattern, we display a single digit on the first row, two digits on the second row, and three digits on the third row. This process will repeat until the number of rows is reached.

Note:

  • The count of numbers on each row is equal to the current row number.
  • Also, each number is separated by space.
  • We used a nested loop to print the pattern

Pyramid pattern of numbers

Let’s see how to print the following half-pyramid pattern of numbers

1 
1 2 
1 2 3 
1 2 3 4 
1 2 3 4 5

Note: In each row, every next number is incremented by 1.

Program:

rows = 5
for i in range(1, rows + 1):
    for j in range(1, i + 1):
        print(j, end=' ')
    print('')Code language: Python (python)

Inverted pyramid pattern of numbers

An inverted pyramid is a downward pattern where numbers get reduced in each iteration, and on the last row, it shows only one number. Use reverse for loop to print this pattern.

Pattern

1 1 1 1 1 
2 2 2 2 
3 3 3 
4 4 
5

Program

rows = 5
b = 0
# reverse for loop from 5 to 0
for i in range(rows, 0, -1):
    b += 1
    for j in range(1, i + 1):
        print(b, end=' ')
    print('\r')Code language: Python (python)

Inverted Pyramid pattern with the same digit

Pattern: –

5 5 5 5 5 
5 5 5 5 
5 5 5 
5 5 
5

Program: –

rows = 5
num = rows
# reverse for loop
for i in range(rows, 0, -1):
    for j in range(0, i):
        print(num, end=' ')
    print("\r")
Code language: Python (python)

Another inverted half-pyramid pattern with a number

Pattern: –

0 1 2 3 4 5 
0 1 2 3 4 
0 1 2 3 
0 1 2 
0 1

Program

rows = 5
for i in range(rows, 0, -1):
    for j in range(0, i + 1):
        print(j, end=' ')
    print("\r")
Code language: Python (python)

Alternate numbers pattern using a while loop

Let’s see how to use the while loop to print the number pattern.

Pattern: – 

1 
3 3 
5 5 5 
7 7 7 7 
9 9 9 9 9

Program: –

rows = 5
i = 1
while i <= rows:
    j = 1
    while j <= i:
        print((i * 2 - 1), end=" ")
        j = j + 1
    i = i + 1
    print('')
Code language: Python (python)

Reverse number pattern

Let’s see how to display the pattern of descending order of numbers

Pattern 1: – 

5 5 5 5 5 
4 4 4 4 
3 3 3 
2 2 
1

This pattern is also called as a inverted pyramid of descending numbers.

Program: –

rows = 5
# reverse loop
for i in range(rows, 0, -1):
    num = i
    for j in range(0, i):
        print(num, end=' ')
    print("\r")
Code language: Python (python)

Reverse Pyramid of Numbers

Pattern 2: –

1 
2 1 
3 2 1 
4 3 2 1 
5 4 3 2 1

Note: It is a downward increment pattern where numbers get increased in each iteration. At each row, the amount of number is equal to the current row number.

Program

rows = 6
for i in range(1, rows):
    for j in range(i, 0, -1):
        print(j, end=' ')
    print("")
Code language: Python (python)

Another reverse number pattern

Pattern: –

5 4 3 2 1 
4 3 2 1 
3 2 1 
2 1 
1

Program: –

rows = 5
for i in range(0, rows + 1):
    for j in range(rows - i, 0, -1):
        print(j, end=' ')
    print()Code language: Python (python)

Print reverse number from 10 to 1

Pattern: –

1
3 2
6 5 4
10 9 8 7

Program: –

start = 1
stop = 2
current_num = stop
for row in range(2, 6):
    for col in range(start, stop):
        current_num -= 1
        print(current_num, end=' ')
    print("")
    start = stop
    stop += row
    current_num = stopCode language: Python (python)

Number triangle pattern

Let’s see how to print the right-angled triangle pattern of numbers

Pattern: – 

          1 
        1 2 
      1 2 3 
    1 2 3 4 
  1 2 3 4 5

Program: – 

rows = 6
for i in range(1, rows):
    num = 1
    for j in range(rows, 0, -1):
        if j > i:
            print(" ", end=' ')
        else:
            print(num, end=' ')
            num += 1
    print("")
Code language: Python (python)

Pascal’s triangle pattern using numbers

To build the pascal triangle, start with “1” at the top, then continue placing numbers below it in a triangular pattern.

Each number is the numbers directly above it added together.

Pattern:

1 
1 1 
1 2 1 
1 3 3 1 
1 4 6 4 1 
1 5 10 10 5 1 
1 6 15 20 15 6 1

Program: –

def print_pascal_triangle(size):
    for i in range(0, size):
        for j in range(0, i + 1):
            print(decide_number(i, j), end=" ")
        print()


def decide_number(n, k):
    num = 1
    if k > n - k:
        k = n - k
    for i in range(0, k):
        num = num * (n - i)
        num = num // (i + 1)
    return num

# set rows
rows = 7
print_pascal_triangle(rows)
Code language: Python (python)

Square pattern with numbers

Pattern: –

1 2 3 4 5 
2 2 3 4 5 
3 3 3 4 5 
4 4 4 4 5 
5 5 5 5 5

Program: –

rows = 5
for i in range(1, rows + 1):
    for j in range(1, rows + 1):
        if j <= i:
            print(i, end=' ')
        else:
            print(j, end=' ')
    print()
Code language: Python (python)

Multiplication table pattern

Pattern: –

1  
2  4  
3  6  9  
4  8  12  16  
5  10  15  20  25  
6  12  18  24  30  36  
7  14  21  28  35  42  49  
8  16  24  32  40  48  56  64

Program: –

rows = 8
# rows = int(input("Enter the number of rows "))
for i in range(1, rows + 1):
    for j in range(1, i + 1):
        # multiplication current column and row
        square = i * j
        print(i * j, end='  ')
    print()
Code language: Python (python)

Pyramid pattern of stars in python

This section will see how to print pyramid and Star (asterisk) patterns in Python. Here we will print the following pyramid pattern with Star (asterisk).

  • Half pyramid pattern with stars(*)
  • Full pyramid pattern with stars
  • Inverted pyramid Pattern with stars
  • Triangle pattern with stars
  • Right-angled triangle pattern with stars

Simple half pyramid pattern: – 

* 
* * 
* * * 
* * * * 
* * * * *

This pattern is also known as a right angle triangle pyramid.

Program: –

# number of rows
rows = 5
for i in range(0, rows):
    # nested loop for each column
    for j in range(0, i + 1):
        # print star
        print("*", end=' ')
    # new line after each row
    print("\r")
Code language: Python (python)

Right triangle pyramid of Stars

Pattern: –

        * 
      * * 
    * * * 
  * * * * 
* * * * *

This pattern is also called as mirrored right triangle

Program: – 

# number of rows
rows = 5
k = 2 * rows - 2
for i in range(0, rows):
    # process each column
    for j in range(0, k):
        # print space in pyramid
        print(end=" ")
    k = k - 2
    for j in range(0, i + 1):
        # display star
        print("* ", end="")
    print("")
Code language: Python (python)

Alternative Solution:

rows = 5
for j in range(1, rows+1):
    print("* " * j)Code language: Python (python)

Downward half-Pyramid Pattern of Star

Pattern: –

* * * * *  
* * * *  
* * *  
* *  
*

Note: We need to use the reverse nested loop to print the downward pyramid pattern of stars

Program: –

rows = 5
for i in range(rows + 1, 0, -1):
    # nested reverse loop
    for j in range(0, i - 1):
        # display star
        print("*", end=' ')
    print(" ")
Code language: Python (python)

Downward full Pyramid Pattern of star

Let’s see how to print reversed pyramid pattern in Python.

Pattern: – 

        * * * * * * 
         * * * * * 
          * * * * 
           * * * 
            * * 
             *

Program:

rows = 5
k = 2 * rows - 2
for i in range(rows, -1, -1):
    for j in range(k, 0, -1):
        print(end=" ")
    k = k + 1
    for j in range(0, i + 1):
        print("*", end=" ")
    print("")
Code language: Python (python)

Right down mirror star Pattern

Pattern: – 

*****
 ****
  ***
   **
    *

In this pattern, we need to use two nested while loops.

Program: –

rows = 5
i = rows
while i >= 1:
    j = rows
    while j > i:
        # display space
        print(' ', end=' ')
        j -= 1
    k = 1
    while k <= i:
        print('*', end=' ')
        k += 1
    print()
    i -= 1
Code language: Python (python)

Equilateral triangle pattern of star

Pattern: –

            *   
           *  *   
          *  *  *   
         *  *  *  *   
        *  *  *  *  *   
       *  *  *  *  *  *   
      *  *  *  *  *  *  *

Program: –

print("Print equilateral triangle Pyramid using asterisk symbol ")
# printing full Triangle pyramid using stars
size = 7
m = (2 * size) - 2
for i in range(0, size):
    for j in range(0, m):
        print(end=" ")
    # decrementing m after each loop
    m = m - 1
    for j in range(0, i + 1):
        print("* ", end=' ')
    print(" ")
Code language: Python (python)

Print two pyramids of stars

Pattern: –

*  
* *  
* * *  
* * * *  
* * * * *  
* * * * * *  
 
* * * * * *  
* * * * *  
* * * *  
* * *  
* *  
*

Program: –

rows = 6
for i in range(0, rows):
    for j in range(0, i + 1):
        print("*", end=' ')
    print(" ")

print(" ")

for i in range(rows + 1, 0, -1):
    for j in range(0, i - 1):
        print("*", end=' ')
    print(" ")
Code language: Python (python)

Right start pattern of star

Pattern: –

* 
* * 
* * * 
* * * * 
* * * * * 
* * * * 
* * * 
* * 
*

We also call this pattern as a right pascal’s triangle.

Program: –

rows = 5
for i in range(0, rows):
    for j in range(0, i + 1):
        print("*", end=' ')
    print("\r")

for i in range(rows, 0, -1):
    for j in range(0, i - 1):
        print("*", end=' ')
    print("\r")
Code language: Python (python)

Left triangle pascal’s pattern

Pattern: –

        * 
      * * 
    * * * 
  * * * * 
* * * * * 
  * * * * 
    * * * 
      * * 
        *

Program: –

rows = 5
i = 1
while i <= rows:
    j = i
    while j < rows:
        # display space
        print(' ', end=' ')
        j += 1
    k = 1
    while k <= i:
        print('*', end=' ')
        k += 1
    print()
    i += 1

i = rows
while i >= 1:
    j = i
    while j <= rows:
        print(' ', end=' ')
        j += 1
    k = 1
    while k < i:
        print('*', end=' ')
        k += 1
    print('')
    i -= 1
Code language: Python (python)

Sandglass pattern of star

Pattern: –

* * * * * 
 * * * * 
  * * * 
   * * 
    * 
    * 
   * * 
  * * * 
 * * * * 
* * * * *

To print this pattern we need to use two set of three while loops.

Program: –

rows = 5
i = 0
while i <= rows - 1:
    j = 0
    while j < i:
        # display space
        print('', end=' ')
        j += 1
    k = i
    while k <= rows - 1:
        print('*', end=' ')
        k += 1
    print()
    i += 1

i = rows - 1
while i >= 0:
    j = 0
    while j < i:
        print('', end=' ')
        j += 1
    k = i
    while k <= rows - 1:
        print('*', end=' ')
        k += 1
    print('')
    i -= 1
Code language: Python (python)

Pant style pattern of stars

Pattern: –

****************
*******__*******
******____******
*****______*****
****________****
***__________***
**____________**
*______________*

Program: –

rows = 14
print("*" * rows, end="\n")
i = (rows // 2) - 1
j = 2
while i != 0:
    while j <= (rows - 2):
        print("*" * i, end="")
        print("_" * j, end="")
        print("*" * i, end="\n")
        i = i - 1
        j = j + 2Code language: Python (python)

Diamond-shaped pattern of stars

Pattern: – 

        * 
       * * 
      * * * 
     * * * * 
    * * * * * 
   * * * * * * 
    * * * * * 
     * * * * 
      * * * 
       * * 
        *

Program: –

rows = 5
k = 2 * rows - 2
for i in range(0, rows):
    for j in range(0, k):
        print(end=" ")
    k = k - 1
    for j in range(0, i + 1):
        print("* ", end="")
    print("")
    
k = rows - 2

for i in range(rows, -1, -1):
    for j in range(k, 0, -1):
        print(end=" ")
    k = k + 1
    for j in range(0, i + 1):
        print("* ", end="")
    print("")Code language: Python (python)

Another diamond pattern of star

Pattern: –

    *
   * *
  *   *
 *     *
*       *
 *     *
  *   *
   * *
    *

Program: –

rows = 5
i = 1
while i <= rows:
    j = rows
    while j > i:
        # display space
        print(' ', end=' ')
        j -= 1
    print('*', end=' ')
    k = 1
    while k < 2 * (i - 1):
        print(' ', end=' ')
        k += 1
    if i == 1:
        print()
    else:
        print('*')
    i += 1

i = rows - 1
while i >= 1:
    j = rows
    while j > i:
        print(' ', end=' ')
        j -= 1
    print('*', end=' ')
    k = 1
    while k <= 2 * (i - 1):
        print(' ', end=' ')
        k += 1
    if i == 1:
        print()
    else:
        print('*')
    i -= 1
Code language: Python (python)

Alphabets and letters pattern

In Python, there are ASCII values for each letter. To print the patterns of letters and alphabets, we need to convert them to their ASCII values.

  • Decide the number of rows
  • Start with ASCII number 65 ( ‘A’)
  • Iterate a loop and in nested for loop use the char function to convert ASCII number to its equivalent letter.

Let’ see now how to print alphabets and letters patterns in Python.

Pattern: –

A  
B C  
D E F  
G H I J  
K L M N O  
P Q R S T U  
V W X Y Z [ \

This pattern is knows as right-angled pattern with characters.

Program: –

# ASCII number of 'A'
ascii_number = 65
rows = 7
for i in range(0, rows):
    for j in range(0, i + 1):
        character = chr(ascii_number)
        print(character, end=' ')
        ascii_number += 1
    print(" ")Code language: Python (python)

Pattern to display letter of the word

Let’s see how to print word ‘Python’ in Pattern: –

P
Py
Pyt
Pyth
Pytho
Python

Program: –

word = "Python"
x = ""
for i in word:
    x += i
    print(x)
Code language: Python (python)

Equilateral triangle pattern of characters/alphabets

Pattern: –

            A  
           B C  
          D E F  
         G H I J  
        K L M N O  
       P Q R S T U  
      V W X Y Z [ \

Program: –

print("Print equilateral triangle Pyramid with characters ")
size = 7
asciiNumber = 65
m = (2 * size) - 2
for i in range(0, size):
    for j in range(0, m):
        print(end=" ")
    m = m - 1
    for j in range(0, i + 1):
        character = chr(asciiNumber)
        print(character, end=' ')
        asciiNumber += 1
    print(" ")Code language: Python (python)

Pattern of same character

Pattern: –

V 
V V 
V V V 
V V V V 
V V V V V

Program: –

# Same character pattern
character = 'V'
# convert char to ASCII
char_ascii_no = ord(character)
for i in range(0, 5):
    for j in range(0, i + 1):
        # Convert the ASCII value to the character
        user_char = chr(char_ascii_no)
        print(user_char, end=' ')
    print()Code language: Python (python)

Let’s see some more miscellaneous patterns

More miscellaneous Patterns

Pyramid of horizontal number tables

Pattern: –

1 
2 4 
3 6 9 
4 8 12 16 
5 10 15 20 25 
6 12 18 24 30 36 
7 14 21 28 35 42 49 
8 16 24 32 40 48 56 64 
9 18 27 36 45 54 63 72 81 
10 20 30 40 50 60 70 80 90 100

Program: –

# Pyramid of horizontal tables of numbers
rows = 10
for i in range(1, rows + 1):
    for j in range(1, i + 1):
        print(i * j, end=' ')
    print()
Code language: Python (python)

Double the number pattern

Pattern: –

   1 
   2    1 
   4    2    1 
   8    4    2    1 
  16    8    4    2    1 
  32   16    8    4    2    1 
  64   32   16    8    4    2    1 
 128   64   32   16    8    4    2    1

Note: In each column, every number is double it’s the preceding number.

Program: –

rows = 9
for i in range(1, rows):
    for j in range(-1 + i, -1, -1):
        print(format(2 ** j, "4d"), end=' ')
    print("")Code language: Python (python)

Random number pattern

   1 
   1    2    1 
   1    2    4    2    1 
   1    2    4    8    4    2    1 
   1    2    4    8   16    8    4    2    1 
   1    2    4    8   16   32   16    8    4    2    1 
   1    2    4    8   16   32   64   32   16    8    4    2    1 
   1    2    4    8   16   32   64  128   64   32   16    8    4    2    1

Program: –

rows = 9
for i in range(1, rows):
    for i in range(0, i, 1):
        print(format(2 ** i, "4d"), end=' ')
    for i in range(-1 + i, -1, -1):
        print(format(2 ** i, "4d"), end=' ')
    print("")Code language: Python (python)

Pyramid of numbers less than 10

Pattern: –

1 
2 3 4 
5 6 7 8 9

Program: –

current_num = 1
stop = 2
rows = 3

for i in range(rows):
    for column in range(1, stop):
        print(current_num, end=' ')
        current_num += 1
    print("")
    stop += 2
Code language: Python (python)

Pyramid of numbers up to 10

Pattern: –

1 
2 3 
4 5 6 
7 8 9 10

Program: –

current_num = 1
rows = 4
stop = 2
for i in range(rows):
    for column in range(1, stop):
        print(current_num, end=' ')
        current_num += 1
    print("")
    stop += 1Code language: Python (python)

Even number pattern

Pattern: –

10 
10 8 
10 8 6 
10 8 6 4 
10 8 6 4 2

Programs: –

rows = 5
last_num = 2 * rows
even_num = last_num
for i in range(1, rows + 1):
    even_num = last_num
    for j in range(i):
        print(even_num, end=' ')
        even_num -= 2
    print("\r")
Code language: Python (python)

Unique pyramid pattern of digits

Pattern: –

1 
1 2 1 
1 2 3 2 1 
1 2 3 4 3 2 1 
1 2 3 4 5 4 3 2 1

Program: –

rows = 6
for i in range(1, rows + 1):
    for j in range(1, i - 1):
        print(j, end=" ")
    for j in range(i - 1, 0, -1):
        print(j, end=" ")
    print()
Code language: Python (python)

Pattern double number on each column

Pattern: –

0  
0  1  
0  2  4  
0  3  6   9  
0  4  8   12  16  
0  5  10  15  20  25  
0  6  12  18  24  30  36

Program: –

rows = 7
for i in range(0, rows):
    for j in range(0, i + 1):
        print(i * j, end='  ')
    print()Code language: Python (python)

Number reduction pattern

Pattern: –

1 2 3 4 5 
2 3 4 5 
3 4 5 
4 5 
5

Program: –

rows = 5
for i in range(0, rows + 1, 1):
    for j in range(i + 1, rows + 1, 1):
        print(j, end=' ')
    print()Code language: Python (python)

Pant style pattern of numbers

Pattern: –

5 4 3 2 1 1 2 3 4 5 

5 4 3 2     2 3 4 5 

5 4 3         3 4 5 

5 4             4 5 

5                 5

Program: –

rows = 6
for i in range(0, rows):
    for j in range(rows - 1, i, -1):
        print(j, '', end='')
    for l in range(i):
        print('    ', end='')
    for k in range(i + 1, rows):
        print(k, '', end='')
    print('\n')Code language: Python (python)

Pattern with a combination of numbers and stars

Pattern: –

1 * 2 * 3 * 4 

1 * 2 * 3 

1 * 2 

1

Program: –

row = 4
for i in range(0, row):
    c = 1
    print(c, end=' ')
    for j in range(row - i - 1, 0, -1):
        print('*', end=' ')
        c = c + 1
        print(c, end=' ')
    print('\n')
Code language: Python (python)

Also, see how to calculate the sum and average in Python.

Practice Problem

Pattern: –

0 
2 4 
4 8 8 
8 16 16 16

Solution: –

num = 4
counter = 0
for x in range(0, num):
    for y in range(0, x + 1):
        print(counter, end=" ")
        counter = 2 ** (x + 1)
    print()Code language: Python (python)

Next Steps

Solve:

If you don’t find the pattern you are looking for, let me know by leaving a comment and questions below.

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About Vishal

I’m Vishal Hule, the Founder of PYnative.com. As a Python developer, I enjoy assisting students, developers, and learners. Follow me on Twitter.

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Comments

  1. Recep says

    “”” places you need to enter “””
    z = “-”
    y = “|” # vertical_character
    x = “_” # horinzontal_character
    roof = 3 # roof_length
    word = “recepdeniz”
    “”” ************************ “””

    word = f”{z}”.join(word)
    sag = y+x
    sol = x+y
    w_index = 0
    print(” ” * ((roof * 2)-1) , f”{x}” * 3)
    for i in range(1, roof+1):
    print(” ” * (2*(roof-i)) ,sol ,sag * (i-1) ,f”|{word[i-1]}|”, sol * (i-1), sag, sep=””)
    w_index += 1
    for j in range(1, (len(word) – (roof-1))):
    print(sag * roof ,f”|{word[w_index]}|”, sol * roof, sep=””)
    w_index += 1
    for l in range(1):
    print(f”{y}”, f”{x}” * ((roof * 5) – (roof-1)), f”{y}”, sep=””)

    # output —>

    ___
    _||r||_
    _||_|-|_||_
    _||_|_|e|_|_||_
    |_|_|_|-|_|_|_|
    |_|_|_|c|_|_|_|
    |_|_|_|-|_|_|_|
    |_|_|_|e|_|_|_|
    |_|_|_|-|_|_|_|
    |_|_|_|p|_|_|_|
    |_|_|_|-|_|_|_|
    |_|_|_|d|_|_|_|
    |_|_|_|-|_|_|_|
    |_|_|_|e|_|_|_|
    |_|_|_|-|_|_|_|
    |_|_|_|n|_|_|_|
    |_|_|_|-|_|_|_|
    |_|_|_|i|_|_|_|
    |_|_|_|-|_|_|_|
    |_|_|_|z|_|_|_|
    |_____________|

    this code output is looking bad on this comment

    Reply

  5. Komal Bansal says

    1 1
    1 2 2 1
    1 2 3 3 2 1
    1 2 3 4 4 3 2 1
    1 2 3 4 5 5 4 3 2 1

    code:-

    n=int(input())
    for i in range(1,n+1):
    for j in range(1,i+1):
    print(j,end=” “)
    for j in range(2*(n-i)):
    print(” “,end=” “)
    for j in range(i,0,-1):
    print(j,end=” “)
    print()

    Reply

    • will smith says

      n = 5
      for i in range(1,n+1):
      for j in range(1,i+1):
      print(j,end=’ ‘)
      for j in range(i,0,-1):
      print(j,end=’ ‘)
      print()

      this is easy I thing what your opinion

      Reply

    • asa says

      n=5
      start_char=ord(“A”)
      for i in range(n,0,-1):
      for j in range(n-1):
      print(” “,end=” “)
      for j in range(i,n+1):
      print(chr(start_char+j-1),end=” “)
      print()

      Reply

    • Sid says

      n=int(input(“Enter the number of rows :”)
      for i in range(1,n+1):
      for j in range((n+1-i),(n+1)):
      print(chr(64+j),end=” “)
      print()

      Reply

  8. Himesh c. says

    rows = int(input(“enter the number of rows: “))
    for i in range(1, rows + 1):
    for j in range(1, i + 1):
    print(i * j, end=’ ‘)
    print()

    Reply

  9. Amarnath Ganta says

    Please write code for this pattern in python:

    #.#.#.#.#.#.#.#.#
    #.#.#.#…#.#.#.#
    #.#.#………..#.#.#
    #.#……………..#.#
    #…………………#
    #.#……………..#.#
    #.#.#……….#.#.#
    #.#.#.#…#.#.#.#
    #.#.#.#.#.#.#.#.#

    Reply

    • Kevin John says

      I did get the output like this . Here is the Code . Hope it Helps

      for i in range(1,5):
      for j in range(5-i):
      if j%2 == 0:
      print(‘#’,end=” “)
      else:
      print(‘.’,end=” “)
      for j in range(2*i-1):
      if i == 1:
      print(‘#’,end=” “)
      else:
      print(‘.’,end=” “)
      for j in range(5-i,0,-1):
      if j%2 == 0:
      print(‘.’,end=” “)
      else:
      print(‘#’,end=” “)
      print()
      for i in range(3,0,-1):
      for j in range(5-i):
      if j%2 == 0:
      print(‘#’,end=” “)
      else:
      print(‘.’,end=” “)
      for j in range(2*i-1):
      if i == 1:
      print(‘#’,end=” “)
      else:
      print(‘.’,end=” “)
      for j in range(5-i,0,-1):
      if j%2 == 0:
      print(‘.’,end=” “)
      else:
      print(‘#’,end=” “)
      print()

      Reply

  10. M says

    Sorry I couldn’t find the box to leave my question there so I replied to this comment
    I wanna print out in this form

    3
    5
    7
    I don’t know where I am doing wrong that my codes don’t work at all
    I’ll appreciate if you answer

    Reply

    • M says

      Actually the form is not like this, I typed in the correct form don’t know why got like this
      It must be like this imagine these numbers as a square
      1 2 3
      4 5 6
      7 8 9
      Imagine all of these numbers printed in the shape of a square and only the numbers (3, 5, 7) must be printed in the form that they are placed in a square

      Reply

      • Kevin John says

        Here is the answer

        count = 1
        for i in range(1,4):
        for j in range(1,4):
        if i + j == 4:
        print(count,end=” “)
        else:
        print(‘ ‘,end=” “)
        count += 1
        print()

        Reply

    • Vinoth says

      row =5
      num = row

      for i in range(1,row+1):
      for j in range(row):
      print(num,end=” “)
      if(num<row):
      num+=1

      num =row-i
      print("")

      Reply

    • tejesh says

      n=int(input());
      for i in range (0,n):
      for j in range (0,i+1):
      print(n-j,end=’ ‘)
      for j in range (0,n-i-1):
      print(n,end=’ ‘)
      print();

      Reply

    • neelam says

      for loop in range(1,6):
      a=6-loop
      for i in range(loop):
      print(i+a,end=” “)
      for j in range(5,loop,-1):
      print(“5″,end=” “)
      print(“\n”)

      Reply

  13. swapna says

    s = 3 n= 4 write a program to print a inverted hollow pyramid of n rows using numbers starting from s

    Reply

    • Mohd Saud says

      Yes good question
      And the answer is

      n=5
      for i in range(1,n+1):
      if i%2==0:
      for j in range(1,i+1):
      print(j,end=’ ‘)
      print()
      else:
      for j in range(i,0,-1):
      print(j,end=’ ‘)
      print()

      Reply

    • neelam says

      for loop in range(1,6):
      if loop%2==0:
      for i in range(1,loop+1):
      print(i,end=” “)
      print(“\n”)
      else:
      for i in range(loop,0,-1):
      print(i,end=” “)
      print(“\n”)

      Reply

    • neelam says

      for loop in range(1,6):
      if loop%2==0:
      for i in range(1,loop+1):
      print(i,end=” “)
      print(“\n”)
      else:
      for i in range(loop,0,-1):
      print(i,end=” “)
      print(“\n”)

      Reply

    • Sivaraman says

      num = int(input("enter the number:"))
      c = 1

      for i in range(num):
      if i % 2 == 0:
      for j in range(i + 1):
      print(c, end=" ")
      c += 1
      else:
      start_num = c + i
      for j in range(i + 1):
      print(start_num, end=" ")
      start_num -= 1
      c += 1
      print()

      Reply

    • BHagyasri says

      n=int(input())
      c=1
      for i in range(1,n+1):
      string=""
      for j in range(1,i+1):
      string=str(c)+" "+string
      c+=1
      print(string)

      Reply

      • Bhagyasri says

        sorry for the above code mistake in j loop. this is actual code and simple way…….

        n=int(input())
        c=1
        for i in range(1,n+1):
        string=””
        for j in range(i+1,1,-1):
        string=str(c)+” “+string
        c+=1
        print(string)

        Reply

  17. Maneet says

    I have simpler code for

    Your code
    Unique pyramid pattern of digits
    Pattern: –

    1
    1 2 1
    1 2 3 2 1
    1 2 3 4 3 2 1
    1 2 3 4 5 4 3 2 1

    Program: –

    rows = 6
    for i in range(1, rows + 1):
    for j in range(1, i - 1):
    print(j, end=" ")
    for j in range(i - 1, 0, -1):
    print(j, end=" ")
    print()

    my code

    rows = 6
    a = 1
    for i in range(1, rows + 1):
    for j in range(1, i - 1):
    print(j, end=" ")
    print(a**2)
    a = (a*10)+1

    the series you wrote goes like this
    1
    (11)^2
    (111)^3

    .
    I hope my suggestion is valuable
    thanks!!

    Reply

      • Nilesh Morekar says

        s='IAS'
        for i in range(3):
        for j in range(i+1):
        print(s[j+2-i] , end=' ')
        print()
        for i in range(1):
        for j in range(2-i):
        print(s[j+1] , end=' ')
        print()
        print(s[2])

        Reply

    • neelam says

      for loop in range(1,6):
      for i in range(1,loop):
      print(i,end=” “)
      for j in range(loop):
      print(loop-j,end=” “)
      print(“\n”)

      Reply

    • Bhagyasri says

      i wrote dynamic format , user want’s to give any nymber…..

      n=int(input())
      c=1
      for i in range(1,n+1):
      for j in range(1,i*2):
      print(str(c)+" ",end="")
      print(" ")
      c+=1

      Reply

    • neelam says

      n=7
      for loop in range(1,9):
      for i in range(1,loop):
      print(i,end=” “)
      print(“*”*n,end=” “)
      n-=1
      print(“\n”)

      But it is also printing 8 “*” on top of the pyramid. please reply to remove it. else, the pattern is as is.

      Reply

    • neelam says

      n=7
      for loop in range(1,9):
      for i in range(1,loop):
      print(i,end=” “)
      print(“*”*n,end=” “)
      n-=1
      print(“\n”)

      But it is also printing 8 “*” on top of the pyramid. please reply to remove it. else, the pattern is as is.

      Reply

    • Razal says

      row = 5
      for i in range(1,row + 1):
      c = 0
      for j in range(1, i + 1):
      print(i+(5*c), end=’ ‘)
      c += 1
      print()

      Reply

  23. Isna says

    please teach me how to display a pattern by entering a number first, like number 4…use
    pattern = int(input)

    – – – – – 4
    – – – -3 4 5
    — -2 3 4 5 6
    -1 2 3 4 5 6 7

    Reply

  24. Isna says

    please teach me how to display a pattern by entering a number first, like number 4…use pattern = int(input)
    4
    3 4 5
    2 3 4 5 6
    1 2 3 4 5 6 7

    Reply

    • jahangeer alam says

      n=int(input("enter the number"))
      k=int(input("enter the number"))
      a=n+k
      b=a
      for i in range(1,n+1):
      if i<k:
      print(a)
      a=a+b
      elif i==k:
      print(k)
      else:
      a=a-b
      print(a)

      Reply

    • Armaan Indani says

      x=int(input("input= "))
      mid=x//2+1
      for i in range(1,mid):
      print(i,i)
      print(mid)
      for i in range(mid-1,0,-1):
      print(i,i)

      Reply

      • neelam says

        n=3
        for loop in range(1,8):
        if loop<4:
        for i in range(1,3):
        print(loop,end=" ")
        print("\n")
        elif loop==4:
        print("4",end=" ")
        print("\n")
        else:
        for i in range(1,3):
        print(n,end=" ")
        n-=1
        print("\n")

        Reply

    • nagasai says

      n=int(input())
      for i in range(n):
      for j in range(i+1):
      if j==0:print(‘*’,end=””)
      else:print(j,end=””)
      for j in range(i):
      if j==i-1:
      print(“*”,end=””)
      else:
      print(i-j-1,end=””)
      print()
      x=n-1
      for i in range(x):
      for j in range(x-i):
      if j==0:
      print(“*”,end=””)
      else:
      print(j,end=””)
      for j in range(x-i-1):
      if j==x-i-2:
      print(“*”,end=””)
      else:
      print(x-i-2-j,end=””)

      print()

      Reply

  30. christian says

    an alternative solution to the random number pattern.

    for i in range(1,9):
    k = 2
    for j in range(i*2-1):
    if 2**j=2**i:
    print(2**(i-k),'',end='')
    k = k + 1
    print()

    Reply

  31. christian says

    an alternative solution to: “Print reverse number from 10 to 1”

    k = 0
    for i in range(5):
    for j in range(i):
    print(k+i-j,'',end='')
    k = k+i
    print()

    Reply

  32. luliao says

    How can you get this output:
    enter a number: 50

    1
23
456
78910
1112131415
161718192021
22232425262728
2930313233343536
373839404142434445
4647484950
    Reply

    • Armaan Indani says

      x=1
      brk=False
      n=int(input("Enter the number: "))
      for i in range(n):
      for j in range(i):
      if x<=n:
      print(x,end='')
      x+=1
      else:
      brk=True
      break
      if brk==True:
      break
      print()

      Reply

  33. Jackson says

    Can anyone help me make a pyramid where the length of the left side scales based on a entered integer using loops? ex
    Enter an integer between 1 and 5: 5

                1
         2 3
      3 4 5
   4 5 6 7
5 6 7 8 9
    Reply

      • Armaan Indani says

        x=int(input("Enter Number of rows: "))
        for i in range(x):
        print(" "*(2*i),end="")
        for j in range(2*(x-i)-1):
        print(2*(x-i)-1,end=" ")
        print()

        Reply

    • Armaan Indani says

      n=int(input("Enter Number of rows(odd): "))
      x=n//2
      for i in range(x):
      print(" "*(x-i),end="")
      print("*"*(2*i+1))
      print("&"*(2*x+1))
      for i in range(x-1,-1,-1):
      print(" "*(x-i),end="")
      print("*"*(2*i+1))

      Reply

    • neelam says

      for loop in range(6):
      print(“1″,end=” “)
      for gap in range(0,loop):
      print(” “,end=” “)
      print(loop+1,end=” “)
      print(“\n”)

      Reply

    • Reddy says

      a="#@"
      c=""
      for i in range(int(input())):
      if i%2==0:
      b=a[0]
      else:
      b=a[1]
      c=c+b
      print(c)
      #in place of the index, you can directly assign them separately

      Reply

    • Reddy says

      b=int(input())
      n=""
      m=1
      a=0
      for i in range(1,b+1):
      n=n+ str(i)
      m=m*i
      a=a+ i
      print(n+" "*(b)+str(m)+" "*(b)+str(a))
      I cannot maintain the spaces, if any one knows, please mention it.

      Reply

  41. muditha says

    Complete the code to find if a given number is a prime number? The program will take a positive integer greater than 1 as input and indicate if it is a prime number by saying “prime”, and if it is not a prime number saying “not a prime”. Note there are 3 places in the given code that you need to fix for this code to work properly and give the expected output.

    
i = int(input())
j = 5 # fix the code (1) 
while (j  i/j): 
    print ("prime")
    Reply

  42. muditha says

    Complete the code to find if a given number is a prime number? The program will take a positive integer greater than 1 as input and indicate if it is a prime number by saying “prime”, and if it is not a prime number saying “not a prime”. Note there are 3 places in the given code that you need to fix for this code to work properly and give the expected output.

    i = int(input())
j = 5 # fix the code (1) 
while (j  i/j): 
    print ("prime")
    Reply

  43. muditha says

    how to print this
    input result

    *
**
**
    *****
*****
*****
*****
*****
    val = int(input())
for x in range (0, val):
print(‘*’,end=”)
val = int(input())
for x in range (0, val):
    print('*',end='')

    please help to fill this code

    Reply

  44. Muskan Agrawal says

    Write a program to print the below number pattern
    for n=6

    1
3   5
7   9   11
1   3   5    7
9   11  1   3   5 
7   9    11  1   3   5

    Use a variable ‘n’ in the program to control the number of output rows
    As here for n=6, the number of rows is 6

    Reply

  50. farah says

    please i need answer:
    Write a program to display a shape using star (*) based on the user selection. The program
    will repeatedly ask the user to determine the shape number (any number from 1-6, see
    below) and its parameters (i.e. width, height). The program will stop asking the user for
    more inputs only when the user inputs 7 (which means exit).
    The user will see the following menu:
    1: Square
    2: Rectangle
    3: Left Lower Triangle
    4: Right Lower Triangle
    5: Left Upper Triangle
    6: Right Upper Triangle
    7: Exit
    Enter the number of the shape you want to be drawn on the screen:
    – In case the user selected 1, you will ask the user to enter the length of the square,
    and your program will then call a function that will draw the square based on the
    given length.
    – In case the user selected 2, you will ask the user to enter the width and the height of
    the rectangle and your program will then call a function that will draw the rectangle
    based on the given width and height
    – In case the user selected 3 or 4 or 5 or 6, you will ask the user to enter the length of
    the triangle. In your code, you will write 4 functions to draw the corresponding 4
    triangle types based on the given length.
    For example, given a length=5
    o Left Lower Triangle function will draw:

     *
 * *
 * * *
 * * * *
* * * * *

    o Right Lower Triangle will draw:

    *
* *
* * *
* * * *
* * * * *

    o Left Upper Triangle will draw:

    * * * * *
* * * *
* * *
* *
*

    o Right Upper Triangle will draw:

    * * * * *
 * * * *
 * * *
 * *
 *

    – In case the user selected 7, your program should stop running
    – In case the user selected a number, not in the range (1-7), your program will print a
    message “invalid selection, try again”, and the menu should be displayed again.
    – After a user select any of the number 1-6, and after drawing the required shape, the
    the menu should be displayed again asking the user for a new selection.

    Reply

  51. MB says

    I’m looking to solve the following:

    Write a program that accepts a positive integer, N, that represents the number of rows of a right triangle. Each row of the triangle consists of one or more ‘*’ characters. Use a while loop or a for loop, to print the right triangle of the character ‘*’ where the triangle is one character wide at its narrowest point and N characters wide at its widest point. Then, display a blank line followed by the number of times the ‘*’ character is shown in the triangle.

    Sample Input – 9
    Sample output:

    *
**
***
****
*****
******
*******
********
*********

    45
    ____________________________________

    What I have so far:

    N = 9
for i in range(0, N +1):
    for j in range(1, i + 1):
        print("*", end='')
    print('')
print ('')

    _________________________________

    *
**
***
****
*****
******
*******
********
*********

    >>>
    __________________________________

    Not sure how to calculate or display the total number of (*’s) listed.

    Also, not sure if needed, but it would be cool to have a message printed stating that “only positive integers are accepted in this code”, if a negative integer is input as a value for ‘N’. Or something like this. Just trying to add some flair to the program.

    Reply

    • Armaan Indani says

      n=9
      count=0
      for i in range(n+1):
      for j in range(1,i+1):
      print("*", end='')
      count+=1
      print()
      print("Total stars =",count)

      Just increase the count by 1 each time you print a star

      Reply

    • Karanbir says 

      
count=1
flag=0
num=int(input('Enter number:'))
row=(num)
col=2
for i in range(row):
    for j in range(col):
        if flag==0:
            print(count,end='')
        else:
            print('*',end='')
            
    if i%2==0:
        flag=1
        count+=1
    else:
        flag=0
    col+=1
    print('\r')
      Reply

    • Athena says 

      for i in range(5):
    for j in range(i+1, 7):
        print(j, end="")
    print()
for i in range(6):
    for j in range(6-i, 7):
        print(j, end="")
    print()
      Reply

    • Armaan Indani says

      n=int(input())
      for i in range(n,0,-1):
      for j in range(1,i+1):
      print(n-i+j,end="")
      print()
      for i in range(1,n):
      for j in range(i+1):
      print(n-i+j,end="")
      print()

      Reply

    • Logesh says 

      Inp=int(input())
For I in range(1,Inp+1):
       For j in rage(1,Inp+1,1):
              If i==1 or j==1 or i==Inp or j==Inp:
                  Print("*")
      Reply

    • Deviprasad says

      n=int(input())
      for i in range(1,n+1):
      for j in range(1,n+1):
      if i==1 or j==1 or i==n or j==n:
      print("*",end='')
      else:
      print(' ',end='')
      print()      v

      Reply

  59. Bala bhaskar says

    Hi Vishal, can u please help in solving the following patterns of rows “n”

             *
      *  *
    *    *
  *      *
* * * * *

    and 

    ______
|    /
|   /
|  /
| /
|/
    Reply

    • Athena says 

      print("------")
for i in range(5):
    for j in range(1):
        print("|", end="")
    for j in range(5-i-1, 0, -1):
        print(" ", end="")
    for j in range(1):
        print("/", end="")
    print()
      Reply

  60. adi says

    Pattern double number on each column using while loop 

    
n = int(input()) 
i = 0 
while(i<=n):
    j = 1 
    p = 1 
    while(j1):
            print(p*i,end=" ")
            p=p+1 
        else:
            print(0,end=" ")
        j=j+1 
    print()
    i=i+1
    Reply

    • adi says 

       
n = int(input()) 
i = 0 
while(i<=n):
    j = 1 
    p = 1 
    while(j1):
                print(p*i,end=" ")
                p=p+1 
            else:
               print(0,end=" ")
            j=j+1 
    print()
    i=i+1
      Reply

      • adi says

        there is some problem with this website sir
        mine (j<=1) and if the statement is not printing
        Please check asap

        Reply

  61. adi says

    Practise Problem
    Pattern using while loop 

     
n = int(input())
print(0)
i = 1 
q = 2 
while(i<n):
    j = 1 
    p = q 
    while(j1):
            print(p*2,end=" ")
        else:
            print(p,end=" ")
        j=j+1 
    print()
    q=q*2
    i=i+1
    Reply

    • adi says

      the first solution is kind of wrong
      this is the right solution 

      
n = int(input())
print(0)
i = 1 
q = 2 
while(i<n):
    j = 1 
    p = q 
    while(j1):
            print(p*2,end=" ")
        else:
            print(p,end=" ")
        j=j+1 
    print()
    q=q*2
    i=i+1
      Reply

  62. adi says

    Even number pattern using while loop 

     
o = int(input())
n = int(input()) 
i = 1 
q = o 
while(i<=n):
          j = 1 
          p = q
          while(j<=i):
                print(p,end=" ")
                p=p-2
                j=j+1
           print()
           i=i+1
    Reply

  63. adi says

    Double the number pattern using while loop 

    
n = int(input())
print(1)
i = 1 
q = 2 
while(i<n):
         j = 1 
        p = q 
        while(j<=i+1):
                 if(j==(i+1)):
                         print(1,end="") 
                 else: 
                      print(p,end="")
                      p=p//2 
                  j=j+1
         print()
         q=q*2
         i=i+1
    Reply

  64. adi says

    Pattern with a combination of numbers and stars 

    
n = int(input())
i = 1 
p = n 
while(i<=n):
          j = 1
         o = 1 
         while(j<=((p-1)+p)):
                   if(j==1):
                           print(1,end="")
                   elif(j%2==0):
                           print("*",end="")
                   else:
                       print((j-o),end="")
                       o=o+1
                    j=j+1
         print()
         p=p-1
         i=i+1
    Reply

    • adi says

      Here is the solution to this question 

      n = int(input())
i = 1 
p = 1 
while(i<=n):
    j = 1 
    while(j<=p):
        print(i,end=" ")
        j=j+1 
    print()
    p=p+2 
    i=i+1
      Reply

      • adi says 

        n = int(input())
i = 1
p = 1
while(i<=n):
        j = 1
while(j<=p):
        print(i,end=" ")
j=j+1
print()
p=p+2
i=i+1
        Reply

        • adi says 

          n = int(input())
i = 1
p = 1
while(i<=n):
        j = 1
       while(j<=p):
               print(i,end=" ")
               j=j+1
       print()
       p=p+2
       i=i+1
          Reply

          • kabir says 

            
n = int(input())
i = 1
p = 1
while(i<=n):
         j = 1
        while(j<=p):
                print(i,end=" ")
                j=j+1
        print()
        p=p+2
        i=i+1

  66. sai vikas says

    Given an integer N, write a program to print a right angle triangle pattern similar to the pattern shown below

        /|
   / |
  /  |
 /   |
/____|

    Input

    The input will be a single line containing a positive integer (N).
    Output

    The output should be N lines containing the triangle pattern.

    Reply

  67. Ameya Kshatriya says 

    #Star pattern for beginners 
#This prints full pyramid

n=int(input())
s=n-1
for i in range(1,n+1) :
    for j in range(s+1) :
        print(s*' ',i*'* ')
        s=s-1
        i=i+1
    Reply

    • Ashish says 

      row = 5
for i in range(1,row+1):
	for j in range(1,row+1):
		if i > 1 and i  (row-2):
			print(" ", end = "  ")
		else:
			print("*", end = "  ")
	print()
      Reply

    • Shubham says 

      for row in range(5):
    for col in range(5):

        if ((col == 0 or col == 4 or col == 1) and (row != 0 or row != 4) or (row == 0 or row == 4) and (col > 0 and col < 4)):

            print("*", end="")
    else:
            print(end=" ")
    print()
      Reply

    • adi says

      Here is the solution for your question 

      
    n = int(input())
    i = 1 
    q = 1  
    while(i<=n):
          j = 1 
          p = q 
          o = 1 
          while(j<=i):
                  if(i%2==0):
                         print(p,end=" ")
                         p=p-1
                  else:
                        print(o,end=" ")
                        o=o+1 
                  j=j+1 
           print()
           q=q+1 
           i=i+1
      Reply

      • Hinata Uzamaki says 

         
n =int(input()) 
for i in range(1,n+1):
    if(i%2==0):
        for j in range(1,i+1):
            print(i,end="")
            i=i-1
    else:
        for j in range(1,i+1):
            print(j,end="")
    print()
        Reply

    • Avijit says 

      rows = 5
for i in range(1, rows + 1):
    for s in range(1, i+1):
        print("   ", end = ' ')
    for j in range(rows+1, i , -1):
        print('*', end='')
    print()
rows1=rows-1
for i in range(1, rows1 + 1):
    for s in range(rows1+1,i,-1):
        print("   ",end=' ')
    for j in range(0, i+1):
        print('*', end='')
    print()
      Reply

  72. Alsya says

    Can you please help me with this kind of pattern, thank you.

    Enter the number of line: 10

    11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29
30 31 32 33 34 35 36 37
38 39 40 41 42 43 44
45 46 47 48 49 50
51 52 53 54 55
56 57 58 59
60 61 62
63 64
65​
    Reply

  75. Lucky Bawa says

    Can you please help me with this pattern

    1    2    3   4   5    6    7     8     9
10 11 12 13        14  15  16  17
18 19 20                      21 22 23
24 25                                26 27
28                                           29
    Reply

  76. Snehal says

    Hey Vishal,
    My self Snehal. I have been following your pynative work for almost a year now.
    I am a beginner at Python. I sometimes get stuck. I need questions to practice as well.

    You are helping me with this. Especially with patterns. I wanted to try nested for but I didn’t know how to practice. I got it now.

    Thank you so much.

    Reply

  78. Benjamin Odobasic says

    can you draw this in python with for loops

    0 - - - - - - - 1
- 2 - - - - - 3 -
- - 4 - - - 5 - -
- - - 6 - 7 - - -
- - - - 8 - - - -
- - - 9 - 0 - - -
- - 1 - - - 2 - -
- 3 - - - - - 4 -
5 - - - - - - - 6
    Reply

  79. Achraf Ghaleb says

    Please, can you help me to print this pattern :

            *
    ####*####
########*########
    ####*####
        *

    I tested different methods but I can’t have exactly the same pattern
    if possible, I need a code with for and while loop

    I’m a beginner in Python, so I need more methods for learning

    thank you very much

    Reply

  82. Abhishek K Gautam says

    2 loops were never really needed.

    for i in range(5):
    print(str(i+1)*(i+1))
    for i in reversed(range(5)):
    print(str(i+1)*(i+1))
    row=5
for i in range(row):
    print(str(i+1)*(row-i))
    row=5
for i in range(row):
    print(str(row)*(row-i))
    Reply

  83. REVATHY DHAKSHNAMOORTHY says

    Kindly help with the below pattern
    Sample Input 1:
    5
    Sample Output 1:

    ####*++++
###***+++
##*****++
#*******+
*********
    Reply

  87. Ferdinand says

    Write a program that prompts the user for an integer n, and then prints the drawing as shown in the run examples. The drawing is made up of n bars, where the length of the first bar is 1, the second 2, …., n. The maximum possible value of n will be 9.

    3
2 3
1 2 3
    Reply

  90. JUGANTA says

    HELP, Please print the following pattern as it is in python

    *
*  *  *
*  *  *  *  *
*  *  *  *  *  *  *
*  *  *  *  *  *  *  *  *
                *  *  *  *  *
                *  *  *  *  *
                *  *  *  *  *
                 *  *  *  *  *
    Reply

  91. Juganta says

    PLEASE HELP FOR THIS CODE.Uegent please, Write a program in PYTHON to calculate the parking charges of a vehicle. Enter the type of vehicle as a character (like c for car, b for bus, etc.) and read the hours and minutes when the vehicle enters the parking lot. When the vehicle is leaving, enters its leaving time. Calculate the difference between the two timings to calculate the number of hours and minutes for which the vehicle was parked. Calculate the charges based on the following information:

    Vehicle Name Rate till 3 hours Rate after 3 hours
    Truck / bus Rs 20 30
    Car Rs 10 20
    Scooter /cycle/ Motor cycle Rs 5 10

    Reply

    • abhishek says 

      n=int(input('Enter the no of * u need'))
for i in range(0, n):
    for j in range(0, i + 1):
        print("*", end=' ')
    print()

for i in range(n
               , 0, -1):
    for j in range(0, i - 1):
        print("*", end=' ')
    print()
      Reply

  94. roshnai says

    hi!
    your site is really very helpful!
    i have a question,
    can you please tell me that why in 17th question did you use a in range of (i) and then you printed a space?? see because i have value from 0 to 6 and if we use this later after printing “j”, what happens to 4 and 5th value of i? like where does this space will be included

    Reply

  96. nv says

    how to print this pattern in python that accepts no of rows to be printed as input

    1   2   3   4   5
     2   3   4   5
          3   4    5
               4    5
                     5
    Reply

  97. sneha says 

    1
1 2 1
1 2 1 3 1 2 1
1 2 1 3 1 2 1 4 1 2 1 3 1 2 1

    can anyone help me to print this pattern for 1st 2nd and nth input terms?

    Reply

  99. saman says

    The output for the first solution is not correct.
    the output from the code:

     
1  
2 2  
3 3 3  
4 4 4 4

    the desired output:

    1 
2 2 
3 3 3 
4 4 4 4 
5 5 5 5 5
    Reply

    • Vishal says

      Hey, Please find below the solution

      currentNumber = 1
stop = 2
rows = 4  # Rows you want in your pattern

for i in range(rows):
    for column in range(1, stop):
        print(currentNumber, end=' ')
        currentNumber += 1
    print("")
    stop += 1
      Reply

      • Hinata Uzamaki says 

         
n = int(input()) 
o = 1
for i in range(1,n+1):
    for j in range(1,i+1,1):
        print(o,end=" ")
        o=o+1
    print()
        Reply

  101. Santosh Thengdi says

    Generating Binomial Distribution
    Description
    Generate a binomial distribution, tested 10 times, given the number of trials(n) and probability(p) of each trial.

    The input will contain seed, n, and p in the same order.

    The output should contain a numpy array with 10 numbers representing the required binomial distribution.

    Hint: You can use numpy’s random number generator here too. Remember to set the seed before generating numbers to ensure the correct output.

    Sample Input:

    0

    10

    0.5

    Sample Output:
    [5 6 5 5 5 6 5 7 8 5]

    Reply

  102. Saily says

    Hello Vishal. I loved your article. I have been struggling with pattern printing questions since some time. Your simple coding steps and explanation in the begining of article has helped me alot. Thanx a lot for the compilation of the pattern printing questions. Great job!!

    Reply

    • kaushik says 

      rows = int(input("Enter number of rows: "))
for i in range(0,rows):
    for j in range(0,rows):
        if(j<rows-i-1):
            print(" ",end=" ")
        else:
            print(i+1,end=" ")
    print()

      #This code is for the question asked by uuu

      Reply

  107. love of my life says

    How to print this using a while loop?

    PPPP#
PPP###
PP#####
P#######
#########
P#######
PP#####
PPP###
PPPP#
    Reply

  108. Bharath says

    Could you please try a diamond pattern in which the stars(‘*’) will have 2 pyramids mounted on each other’s base

    Reply

    • Ram says 

      
def pattern(n):
    k = 2 * n - 2
    x = 0
    for i in range(0, n):
        x += 1
        for j in range(0, k):
            print(end=" ")
        k = k - 1
        for j in range(0, i + 1):
            print(x, end=" ")
        print(" ")
    k = n - 2
    x = n + 2
    for i in range(n, -1, -1):
        x -= 1
        for j in range(k, 0, -1):
            print(end=" ")
        k = k + 1
        for j in range(0, i + 1):
            print(x, end=" ")
        print(" ")
      Reply

    • shubham sachdeva says 

       
n = int(input())
temp = n 

for i in range(1,n+1):
    for j in range(1,i,1):
        for x in range(1,i,2*i):
            print(n-j+1,end="")
    for k in range(2*n - 2*i+2,1,-1):
        print(temp,end="")
    temp = temp -1
    for j in range(i,1,-1):
        for x in range(1,i,2*i):
            print(n-j+2,end="")
    print()
    
temp = 2 
for i in range(n,1,-1):
    for j in range(2,i,1):
        print(n-j+2,end="")
    for k in range(2*n-i,i-3,-1):
        print(temp, end="")
    for x in range(i-1,1,-1):
        print(n-x+2,end="")
    temp = temp+1
    print()
      Reply

  111. stavros says 

    --**
-****
******
-*---*-

    Code for this, please??
    for N=3
    How to build an N height pyramid (N=3) with 2 stars at the top and 2 stars for feet for the second and penultimate columns.
    or for N=4

    ---**
--****
-******
********
-*----*
    Reply

  112. steven says

    for N=3
    How to build an N height pyramid (N=3) with 2 stars at the top and 2 stars for feet for the second and penultimate columns.

        **
  ****
******
 *     *
    Reply

  113. steven says 

    **
  ****
******
  *    *

    How to build an N height pyramid (N=3) with 2 stars at the top and 2 stars for feet for the second and penultimate columns.

    Reply

  116. Rohit Kumar Setthachok says

    How to write a program that prints out the triangle of star(s) depending on the input,
    n, by follow the pattern in the following samples using while-loop
    Sample Run#2

    n: 2
*
***
Sample Run#3
n: 5
*
***
*****
*******
*********
    Reply

  117. Jack says

    How do I print out

    ####################
#########--#########
########----########
#######------#######
######--------######
#####----------#####
####------------####
###--------------###
##----------------##
#------------------#

    as well as 

    0 ##########
1 #########-
2 ########--
3 #######---
4 ######----
5 #####-----
6 ####------
7 ###-------
8 ##--------
9 #---------

    Thank you

    Reply

    • siddharth says 

      a=20 # or  a=int(input()) if it  is a user input question
print("#"*a,end="\n") #its the first line of pattern
i=(a//2)-1
j=2
while(i!=0):
    while(j<=(a-2)):
        print("#"*i,end="")
        print("_"*j,end="")
        print("#"*i,end="\n")
        i=i-1
        j=j+2

      hope this helps 🙂

      Reply

    • Nishant says

      How we can create continue pattern of rainfall effect using a diamond pattern
      Print must be like as

      1  2  3
  1   2
     1
1  2  3
  1  2

      … continue
      Here 1 2 3 represent diamond has to print this type of manner

      Reply

    • naga kalyan says 

      a=int(input())
l1=[*range(1,a+1)]
for i in range(1,a+1):
    for j in range(a,i-1,-1):
        if(i==1):
            print(l1[a-j],end=' ')
        elif(j==a):
            l1[a-j]=i
            print(l1[a-j],end=' ')
        else:
            l1[a-j]=l1[a-j]*l1[a-j-1]
            print(l1[a-j],end=' ')
    print()
      Reply

    • Abhijeet says 

      n = int(input())
i = i + 1
for i in range(0,n+1,1):
        for j in range(i+1,n+1,1):
            print(j,end='')
        print()
      Reply

  131. hassan708 says

    receives an integer n as a parameter and displays a pattern of stars on the screen

    stars(2);
****
**
stars(3);
*********
******
***
stars(4);
****************
************
********
****
    Reply

    • Ghanshyam says 

      print("Enter Limit: ")
n = int(input())
i = 1
while(i<=n):
    j = 1
    while(j<=i):
        print((i*2-1), end="")
        j  = j + 1
    i = i + 1
    print()
      Reply

  136. Shivam Bhirud says

    I have a better code with O(n) complexity to print the pattern given below-

    * 
* * 
* * * 
* * * * 
* * * * * 

code-

n = 5
for j in range(1,n+1):
    print("* " * j)
    Reply

    • Ghanshyam says 

      print("Enter limit: ")
n = int(input())
i  = 1
while(i <= n):
    j = 1
    while (j = j):
            print(format(i, "2d"), end=' ')
        else:
            print(format(j, "2d"), end=' ')
        j = j + 1
    print()
    i = i + 1
      Reply

    • naga kalyan says 

      a=int(input())
for i in range(1,a+1):
    for j in range(1,a+1):
        if(j<=i):
            print(i,end=' ')
        else:
            print(j,end=' ')
    print()
      Reply

    • yash Boomerang dev says

      its pretty simple….
      take your code editor and ask someone to do this for you and take the credit.
      after writing the code press run or f5 then itll be printed.

      Reply

  140. sumana says 

    1
    1  2  1
1  2  3  2 1
    1  2  1
        1

    please help me to write “”bottom part of this diamond of numbers””

    Reply

    • Nar Hari Gautam says 

      for row in range(6):
    for col in range(5):
        if (row==0 or row==5 and col!=0):
            print("*",end="")
        elif(col==0):
            print("*",end="")
        else:
            print(end="")
            
    print()
      Reply

  146. Anju says

    Program for this output Write a program to print the following  pattern: 

                   1
           2     2 
       3     3     3 
     4    4    4    4
    Reply

  147. Jackson says 

    *******O** 
******O*** 
******O*** 
*O******** 
*****O****

    How do make this 5 * 10 grid by using random function and each row have only one ‘O’ and the position are random?

    Reply

  148. Ronak Jain says 

    1 2 3 4 5 6 7 8 9
**2 3 4 5 6 7 8
****3 4 5 6 7
******4 5 6
********5

    what is the code for this pattern in python

    Reply

  149. Ronak Jain says 

    1 2 3 4 5 6 7 8 9
   2 3 4 5 6 7 8
      3 4 5 6 7
         4 5 6
            5

    what is the code for this pattern in python

    Reply

    • naga kalyan says 

      a=int(input())
for i in range(1,a+1):
    for j in range(1,(a*2)-i+1):
        if(j<i):
            print('*',end='*')
        else:
            print(j,end=' ')
    print()
      Reply

    • Shivam Srivastava says 

      for i in range(1,n+1):
    for j in range(1):
        if i==1:
            print(i*"*",end="")
        else:
            print(2*"*",end="")
    print()
      Reply

    • Shivam Srivastava says 

      n=5
for i in range(n):
    for j in range(n):
        if j==i:
            print("1",end="")
        else:
            print("0",end="")
    print()
      Reply

  153. Shazan Hussain says 

    -*******
--******
---*****
----****
-----***
------**
-------+

    plz kindly tell me how to make this?

    Reply

  154. asenluke says

    How can I print this? has to work on Adhesive python
    THIRD

                               * 
                         * * 
                       * * * 
                     * * * * 
                   * * * * * 
                 * * * * * * 
               * * * * * * * 
             * * * * * * * * 
           * * * * * * * * *

    Here is the basis code to use:

    for i in range(3):
   for j in range(3-i):
       print("*", end=" ")
   print("")
    Reply

    • subham subhasis says 

      def pypart(n): 
	for i in range(0, n): 
		for j in range(0, i+1): 
			if j % 2 == 1 :
				print("0 ",end="") 
			else :
				print("1 ",end="") 
		# ending line after each row 
		print("\r") 
  
# Driver Code 
n = 5
pypart(n)
      Reply

  164. Sohair says

    I have some question
    1. why we are using end = ‘ ‘? wht is the purpose of it.
    2. need explanation for 3rd argument in range() ex- rage(1, 11, -1)

    Reply

    • Vishal says

      Hi Sohair, end = ‘ ‘ used to have space between numbers or stars.
      For example, if we executing loop 5 times and in each iteration we are printing
      print("*", end=', ') this statemment. this will print *,*,*,*,*

      For second question range(11, 1, -1) this will print range in reverse order. i.e. 11, 10, 9....0 For better understanding on range function please refer to Python range() function

      Reply

  165. Pri says

    n=3

    @@@ @@@
@@@***@
@@@ @@@

    n=5

    @@@@@ @@@@
@@@@@ @
@@@@@*****@
@@@@@ @
@@@@@ @@@@@

    the print above pattern in python

    Reply

  170. Mary says

    Hello,

    How do you write this function using recursion?

    print("Program to print start pattern: \n");
rows = input("Enter max star to be display on single line")
rows = int (rows)
for i in range (0, rows):
    for j in range(0, i + 1):
        print("*", end=' ')
    print("\r")
for i in range (rows, 0, -1):
    for j in range(0, i -1):
        print("*", end=' ')
    print("\r")

    Thank you,
    Mary

    Reply

    • MOHAMMAD MEHDI says 

      n=int(input("enter a number of row"))
count=1
for row in range(1,n+1):
        for col in range(1,row+count):
            print(row,end="")
        count=count+1
        print()
      Reply

      • manivannan.v says 

        for i in range(4):
  current=4
  increment=0
  for j in range(4):
    print(current-increment,end="")
    if(increment<i):
      increment=increment+1
  print()
        Reply

      • Nitish says 

        n = int(input())
for i in range(1, n):
    num = n
    for j in range(1, n):
        print(num, end='')
        if i > j:
            num-=1

    for j in range(n,n+1):
        print(n+1-i,end='')
    num=n
    for j in range(1,n):
        print(num+1-i,end='')
        if n-ij:
            num-=1
    for j in range(n,n+1):
        print(i+1,end='')
    num=i+1
    for j in range(1,n):
        print(num,end='')
        if j>=i:
            num+=1
    print()
        Reply

  177. KISLAY CHANDAN says

    hey, can anyone help me with this code? It must be done using for and if only.

                0
         1 0 1
      2 1 0 1 2
   3 2 1 0 1 2 3
4 3 2 1 0 1 2 3 4

    I tired and think every stuff but I don’t understand what I am missing. I am having an issue with generating 101, 21012, 3210123, 43211234
    here is my code(which is wrong)

    for i in range (1,6):
    for t in range (i,5):
        print('\t', end="")
    for j in range (0,(2*i-1)):
        print(2*i-1-j, "\t", end="")
    print("")
    Reply

    • Akshay Agrawal says 

      n=int(input("enter no."))
for i in range(0,n+1):
    for j in range(i,0,-1):
        print(j,end="")
    print(0,end="")
    for k in range(1,i+1):
        print(k,end="")
    print()

      enter no.5
0
101
21012
3210123
432101234
54321012345
      Reply

    • Akshay Agrawal says 

      x = int(input("enter no. of rows"))    
n=1
for i in range(1,x*2,2):
    for j in range(0,i):
        print(n,"",end="")
        n=n+1
    print()

      enter no. of rows3
1 
2 3 4 
5 6 7 8 9
      Reply

    • Pankaj says 

      s1 = 0
e1 = 7
s2 = 0
e2 = 0
for x in range(4):
    for y in range(s2,e2):
        print(" ",end="")
    for z in range(s1,e1):
        print("*",end="")
    print()
    s1 += 1
    e1 -= 1
    e2 += 1

s1 -= 1
e1 += 1
e2 -= 1

for x in range(3):

    s1 -= 1
    e1 += 1
    e2 -= 1

    for y in range(s2,e2):
        print(" ",end="")
    for z in range(s1,e1):
        print("*",end="")
    print()
      Reply

    • hemant says 

      # star Program 
def first(n):
		for i in range(0, n):		
			for j in range(i,n ):
				print('* ',end='') 

			print("\r")		

		for i in range(0, n):		
			for j in range(0, i+1):
				print('* ',end='') 

			print("\r")		


inp = input('Enter The Numbers Of Rows ')
inp = int(inp) 
first(inp)
      Reply

    • Akshay Agrawal says 

      n=int(input("enter a number : "))
for i in range(n,0,-1):
    print("*"*i)
for j in range(1,n+1):
    print("*"*j)

      enter a number : 9
*********
********
*******
******
*****
****
***
**
*
*
**
***
****
*****
******
*******
********
*********
      Reply

    • Akshay Agrawal says 

      n=int(input("enter number : "))
for i in range(n,0,-1):
    print("*"*i)
for j in range(1,n+1):
    print("*"*j)

      enter number : 9
*********
********
*******
******
*****
****
***
**
*
*
**
***
****
*****
******
*******
********
*********
      Reply

    • Akshay Agrawal says

      previews commented wrong code by mistake

      n=int(input("enter a number : "))
for i in range(n,0,-2):
    print("*"*i)
for j in range(2,n+1,2):
    print("*"*j)

      *********
*******
*****
***
*
**
****
******
********
      Reply

    • Nat says 

      num=int(input('Enter a number: '))

while num<=0:
    print('Error! Enter a positive number: ')
    num=int(input('Enter a number: '))
for row in range (num):
    for col in range (row):
        print('*', end='')
    print()
for i in range (num,0,-1):
    for j in range (i):
        print('*', end='')
    print()
      Reply

        • Akshay Agrawal says 

          n = int(input("enter a num"))
for i in range(1,n):
    for j in range(1,i+1):
        print(j,end="")
    print()
for i in range(n,0,-1):
    for j in range(1,i+1):
        print(j,end="")
    print()

          enter a num3
1
12
123
12
1
          Reply

    • Akshay Agrawal says 

      n = int(input("enter a num"))
i=1
while i<=n :
    print("* "*i)
    i+=1
j=1
while j<=n :
    print("* "*(n-j))
    j+=1

      * 
* * 
* * * 
* * * * 
* * * * * 
* * * * * * 
* * * * * * * 
* * * * * * 
* * * * * 
* * * * 
* * * 
* * 
*
      Reply

    • Sairam Prudhvi says 

      n = int(input())
k = 0
for i in range(n,0,-1):
    k += 1 
    for j in range(i,0,-1):
        if j <= k:
            print('#',end = '')
    print(' ')
      Reply

    • sandeep says 

      for i in range(1,6):
    for j in range(1,i+1):
        print("*",end=" ")
    print("")

      for x in range(5,1,-1):
    for y in range(1,x):
        print("*", end =" ")
    print("")
      Reply

      • Pulkit Thakur says 

        for i in range(4):
    for j in range(4-i):
        print(chr(65+i),end='')
    for j in range(4-i):
        print("*",end='')
    for j in range(4-i):
        print(chr(65+i),end='')
    print('\n',end='')
        Reply

      • vishal gaddam says 

        counter = 4
char = [" ","D","C","B","A"]
while counter !=0:
	out1 = char[counter] * counter
	out2 = "*" * counter
	print(out1 + out2 + out1)
	counter -=1
        Reply

      • Akshay Agrawal says 

        n=5
for i in range(0,n):
    print(chr(65+i)*(n-i), end="")
    print("*"*(n-i), end="")
    print(chr(65+i)*(n-i), end="")
    print()

        AAAA****AAAA
BBB***BBB
CC**CC
D*D
        Reply

    • vishal gaddam says 

      star = '*'
counter = 1
out = 0
print("Pattern1")
while counter < 6:
	out = counter * star
	print(out)
	counter +=1
counter = 5
while counter !=0:
	out = counter * star
	print(out)
	counter -=1
      Reply

    • himanshu tiwari says 

      n=int(input("enter the number"))
for i in range(1,n+1):
    s= '*'*i
    print(s)
for j in range(n+1,1,-1):
    y = '*' * j
    print(y)
      Reply

    • Akshay Agrawal says 

      n = int(input("enter a num"))
i=1
while i<=n :
    print("*"*i)
    i+=1
j=1
while j<=n :
    print("*"*(n-j))
    j+=1

      enter a num6
*
**
***
****
*****
******
*****
****
***
**
*
      Reply

    • Akshay Agrawal says 

      num=int(input("enter no. of rows : "))
for i in range(num):
    val=i+1
    for j in range(i+1):
        print(format(val, "<4"), end="")
        val=val+((num-1)-j)
    print()

      enter no. of rows : 5
1   
2   6   
3   7   10  
4   8   11  13  
5   9   12  14  15
      Reply

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