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Consecutive Prime Sum

 Published on Friday, 15th August 2003, 06:00 pm; Solved by 69599;
Difficulty level: 2

Problem 50

The prime $41$, can be written as the sum of six consecutive primes:

$$41 = 2 + 3 + 5 + 7 + 11 + 13.$$

This is the longest sum of consecutive primes that adds to a prime below one-hundred.

The longest sum of consecutive primes below one-thousand that adds to a prime, contains $21$ terms, and is equal to $953$.

Which prime, below one-million, can be written as the sum of the most consecutive primes?