{"id":1285,"date":"2016-07-05T08:41:29","date_gmt":"2016-07-05T08:41:29","guid":{"rendered":"http:\/\/engineeringtutorial.com\/?p=1285"},"modified":"2016-10-06T06:39:23","modified_gmt":"2016-10-06T06:39:23","slug":"current-divider-rule","status":"publish","type":"post","link":"https:\/\/instrumentationtools.com\/current-divider-rule\/","title":{"rendered":"Current Divider Rule"},"content":{"rendered":"<p style=\"text-align: justify;\">It can be quite useful to determine how a current entering two parallel resistors\u00a0\u201cdivides\u201d between them.<\/p>\n<p style=\"text-align: justify;\">Consider the circuit shown below:<\/p>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-12007\" src=\"https:\/\/instrumentationtools.com\/wp-content\/uploads\/2016\/07\/instrumentationtools.com_current-divider-rule.png\" alt=\"Current Divider Rule\" width=\"576\" height=\"276\" \/><\/p>\n<p>We replace the parallel connection of\u00a0<em>R<\/em>1\u00a0 \u00a0and\u00a0<em>R<\/em>2 \u00a0by its equivalent resistance.<\/p>\n<p>Thus, Ohm\u2019s Law gives:<\/p>\n<p><img loading=\"lazy\" loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-12008\" src=\"https:\/\/instrumentationtools.com\/wp-content\/uploads\/2016\/07\/instrumentationtools.com_current-divider-rule-equation.png\" alt=\"current-divider-rule-equation\" width=\"435\" height=\"116\" \/><\/p>\n<p>By application of Ohm\u2019s Law again, the current in\u00a0<em>R<\/em>1 \u00a0is <em>i<\/em>1 \u00a0=\u00a0<em>v R<\/em>1\u00a0and thus:<\/p>\n<p><img loading=\"lazy\" loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-12009\" src=\"https:\/\/instrumentationtools.com\/wp-content\/uploads\/2016\/07\/instrumentationtools.com_current-divider-rule-formula.png\" alt=\"current-divider-rule-formula\" width=\"545\" height=\"144\" \/><\/p>\n<p>Similarly, the current in R2 is :<\/p>\n<p><img loading=\"lazy\" loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-12010\" src=\"https:\/\/instrumentationtools.com\/wp-content\/uploads\/2016\/07\/instrumentationtools.com_current-divider-rule-formula-new.png\" alt=\"current-divider-rule-formula-new\" width=\"570\" height=\"135\" \/><\/p>\n<p>These equations describe how the current is divided between the resistors. Because of this, a pair of resistors in parallel is often called a <em>current divider<\/em>. Note that a larger amount of current will exist in the smaller resistor \u2013 thus current tends to take the path of least resistance!<\/p>\n<p style=\"text-align: justify;\"><span style=\"color: #ff0000;\"><strong>Example:<\/strong><\/span><\/p>\n<p>We want to find the current <em>i <\/em>in the circuit below:<\/p>\n<p><img loading=\"lazy\" loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-12011\" src=\"https:\/\/instrumentationtools.com\/wp-content\/uploads\/2016\/07\/instrumentationtools.com_current-divider-rule-circuit.png\" alt=\"current-divider-rule-circuit\" width=\"715\" height=\"260\" \/><\/p>\n<p>The total current delivered by the source is:<\/p>\n<p><img loading=\"lazy\" loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-12012\" src=\"https:\/\/instrumentationtools.com\/wp-content\/uploads\/2016\/07\/instrumentationtools.com_current-divider-rule-equation-2.png\" alt=\"current-divider-rule-equation-2\" width=\"706\" height=\"124\" \/><\/p>\n<p>Therefore the desired current is:<\/p>\n<p><img loading=\"lazy\" loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-12013\" src=\"https:\/\/instrumentationtools.com\/wp-content\/uploads\/2016\/07\/instrumentationtools.com_current-divider-rule-equation-3.png\" alt=\"current-divider-rule-equation-3\" width=\"737\" height=\"110\" \/><\/p>\n","protected":false},"excerpt":{"rendered":"<p>It can be quite useful to determine how a current entering two parallel resistors\u00a0\u201cdivides\u201d between them. Consider the circuit shown below: We replace the parallel connection of\u00a0R1\u00a0 \u00a0and\u00a0R2 \u00a0by its equivalent resistance. Thus, Ohm\u2019s Law gives: By application of Ohm\u2019s Law again, the current in\u00a0R1 \u00a0is i1 \u00a0=\u00a0v R1\u00a0and thus: Similarly, the current in R2 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":12007,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_mo_disable_npp":"","footnotes":""},"categories":[15153],"tags":[17011,17012,17013,17014,17015,17016,17017,17018,17019,17020,17021,17022,17023,12843],"class_list":{"0":"post-1285","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-electronic-devices-circuits","8":"tag-basics-of-current-divider-rule","9":"tag-current-divider-rule","10":"tag-current-divider-rule-circuit","11":"tag-current-divider-rule-definition","12":"tag-current-divider-rule-derivation","13":"tag-current-divider-rule-equation","14":"tag-current-divider-rule-equations","15":"tag-current-divider-rule-for-the-series-parallel-circuit","16":"tag-current-divider-rule-formula","17":"tag-current-divider-rule-principle","18":"tag-current-divider-rule-solved-problems","19":"tag-current-divider-rule-theoy","20":"tag-current-divider-rule-tutorial","21":"tag-electronic-devices-circuits"},"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v27.4 (Yoast SEO v27.4) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>Current Divider Rule - Inst Tools<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/instrumentationtools.com\/current-divider-rule\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Current Divider Rule\" \/>\n<meta property=\"og:description\" content=\"It can be quite useful to determine how a current entering two parallel resistors\u00a0\u201cdivides\u201d between them. Consider the circuit shown below: We replace the parallel connection of\u00a0R1\u00a0 \u00a0and\u00a0R2 \u00a0by its equivalent resistance. Thus, Ohm\u2019s Law gives: By application of Ohm\u2019s Law again, the current in\u00a0R1 \u00a0is i1 \u00a0=\u00a0v R1\u00a0and thus: Similarly, the current in R2 [&hellip;]\" \/>\n<meta property=\"og:url\" content=\"https:\/\/instrumentationtools.com\/current-divider-rule\/\" \/>\n<meta property=\"og:site_name\" content=\"Inst Tools\" \/>\n<meta property=\"article:publisher\" content=\"https:\/\/www.facebook.com\/instrumentationtoolss\/\" \/>\n<meta property=\"article:author\" content=\"https:\/\/www.facebook.com\/instrumentationtoolss\" \/>\n<meta property=\"article:published_time\" content=\"2016-07-05T08:41:29+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2016-10-06T06:39:23+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/instrumentationtools.com\/wp-content\/uploads\/2016\/07\/instrumentationtools.com_current-divider-rule.png\" \/>\n\t<meta property=\"og:image:width\" content=\"576\" \/>\n\t<meta property=\"og:image:height\" content=\"276\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/png\" \/>\n<meta name=\"author\" content=\"Editorial Staff\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:creator\" content=\"@insttools\" \/>\n<meta name=\"twitter:site\" content=\"@insttools\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"Editorial Staff\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\\\/\\\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\\\/\\\/instrumentationtools.com\\\/current-divider-rule\\\/#article\",\"isPartOf\":{\"@id\":\"https:\\\/\\\/instrumentationtools.com\\\/current-divider-rule\\\/\"},\"author\":{\"name\":\"Editorial Staff\",\"@id\":\"https:\\\/\\\/instrumentationtools.com\\\/#\\\/schema\\\/person\\\/41ad3dac301c219e8d41b1ace61655b2\"},\"headline\":\"Current Divider Rule\",\"datePublished\":\"2016-07-05T08:41:29+00:00\",\"dateModified\":\"2016-10-06T06:39:23+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\\\/\\\/instrumentationtools.com\\\/current-divider-rule\\\/\"},\"wordCount\":140,\"commentCount\":0,\"publisher\":{\"@id\":\"https:\\\/\\\/instrumentationtools.com\\\/#organization\"},\"image\":{\"@id\":\"https:\\\/\\\/instrumentationtools.com\\\/current-divider-rule\\\/#primaryimage\"},\"thumbnailUrl\":\"https:\\\/\\\/instrumentationtools.com\\\/wp-content\\\/uploads\\\/2016\\\/07\\\/instrumentationtools.com_current-divider-rule.png\",\"keywords\":[\"Basics of Current Divider Rule\",\"Current Divider Rule\",\"Current Divider Rule Circuit\",\"Current Divider Rule Definition\",\"current divider rule derivation\",\"Current Divider Rule Equation\",\"Current Divider Rule Equations\",\"current divider rule for the series-parallel circuit\",\"Current Divider Rule Formula\",\"Current Divider Rule Principle\",\"current divider rule solved problems\",\"Current Divider Rule Theoy\",\"current divider rule tutorial\",\"Electronic Devices &amp; Circuits\"],\"articleSection\":[\"Electronic Devices &amp; Circuits\"],\"inLanguage\":\"en-US\",\"potentialAction\":[{\"@type\":\"CommentAction\",\"name\":\"Comment\",\"target\":[\"https:\\\/\\\/instrumentationtools.com\\\/current-divider-rule\\\/#respond\"]}]},{\"@type\":\"WebPage\",\"@id\":\"https:\\\/\\\/instrumentationtools.com\\\/current-divider-rule\\\/\",\"url\":\"https:\\\/\\\/instrumentationtools.com\\\/current-divider-rule\\\/\",\"name\":\"Current Divider Rule - 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