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chore: Simplify location uniquing#63263
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varungandhi-src
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Jun 14, 2024
| } | ||
| } | ||
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| return deduplicateLocations(locations), collections.DeduplicateBy(symbols, func(s string) string { return s }), nil |
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Before this, there is a call
locations = append(locations, convertSCIPRangesToLocations(ranges, locationKey.UploadID, locationKey.Path)...)
So all locations have the same UploadID and Path.
kritzcreek
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Jun 14, 2024
| } | ||
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| return deduplicateLocations(locations), collections.DeduplicateBy(symbols, func(s string) string { return s }), nil | ||
| // We only need to unique by the range, since all location objects share the same path and uploadID. |
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| // We only need to unique by the range, since all location objects share the same path and uploadID. | |
| // We only need to deduplicate by range, since all location objects share the same path and uploadID. |
| seen.Add(x) | ||
| filtered = append(filtered, x) | ||
| } | ||
| return filtered |
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Should probably call slices.Clip on the result
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For defensiveness in the case of aliasing? Clipping the result will trigger a copy on future appends.
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Yeah that was my thinking. Honestly slices terrify me...
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If you want to be actually defensive in the case of aliasing, you'd have to construct a copy, and we don't want to do that here. I don't think it's worth taking half-measures like this.
kritzcreek
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Jun 14, 2024
kritzcreek
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Jun 14, 2024
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The code earlier constructing the locations attaches the same
uploadID and path to all of them, so trying to use those while
uniquing is wasteful. Let's stop doing that.
Test plan
Covered by existing tests
Changelog