You can never call your own fn borrow(&mut self, ...) method if you use std::borrow::Borrow; #54103
Description
fn main() {
use std::borrow::Borrow;
struct S;
impl S { fn borrow(&mut self, _: ()) {} }
let mut s = S;
s.borrow(())
}(Just noticed that this might be the intended behaviour, since std::clone::Clone acts the same. But still, the error message here might need to be improved)