interface conversion: expression.Expression is *expression.ScalarFunction, not *expression.Column #29401
Description
Bug Report
Please answer these questions before submitting your issue. Thanks!
1. Minimal reproduce step (Required)
use test;
drop table if exists t;
CREATE TABLE `t` (
`id` int(11) NOT NULL,
`a` bigint(20) DEFAULT NULL,
`b` char(20) DEFAULT NULL,
`c` datetime DEFAULT NULL,
`d` double DEFAULT NULL,
`e` json DEFAULT NULL,
`f` decimal(40,6) DEFAULT NULL,
PRIMARY KEY (`id`) /*T![clustered_index] CLUSTERED */,
KEY `a` (`a`),
KEY `b` (`b`),
KEY `c` (`c`),
KEY `d` (`d`),
KEY `f` (`f`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_bin;
explain select /*+ inl_hash_join(t1) */ * from t t1 join t t2 on t1.b=t2.e;
2. What did you expect to see? (Required)
3. What did you see instead (Required)
mysql> explain select /*+ inl_hash_join(t1) */ * from t t1 join t t2 on t1.b=t2.e;
ERROR 1105 (HY000): interface conversion: expression.Expression is *expression.ScalarFunction, not *expression.Column
4. What is your TiDB version? (Required)
Release Version: v5.3.0-alpha-1311-gb561dface
Edition: Community
Git Commit Hash: b561dface8b0b6408bc067189cf0bcbfd5c6d617
Git Branch: master
UTC Build Time: 2021-11-03 07:33:21
GoVersion: go1.17.2
Race Enabled: false
TiKV Min Version: v3.0.0-60965b006877ca7234adaced7890d7b029ed1306
Check Table Before Drop: false