(fn: Callable[P, ...]) -> ... is considered fully overlapped by (fn: Callable[[], ...]) -> ... #10587
Description
Consider the following example (playground):
class ParamSpecBoundAtDecoratorCallSite(Protocol):
def __call__[**P, T](self, fn: Callable[P, T], /) -> Callable[P, T]: ...
class ParamSpecBoundAtFactoryCallSite[**P](Protocol):
def __call__[T](self, fn: Callable[P, T], /) -> Callable[P, T]: ...
@overload
def f(fn: Callable[[], Any]) -> ParamSpecBoundAtDecoratorCallSite: ...
@overload
def f[**P](fn: Callable[P, Any]) -> ParamSpecBoundAtFactoryCallSite[P]: ...
# error: Overload 2 for "f" will never be used because its parameters overlap overload 1
def f(fn: ...) -> ...: ...This is wrong: The second overload will be reached for all fn which expect at least one argument.