Because of sqlite's flexible typing, even though the column was declared as jsonb, the values are stored as the TEXT-typed json because they're converted to strings by Value/Scan. If the table is strict with a BLOB column, the example fails because of the type mismatch. This can be fixed by using the `jsonb()` function to convert incoming string-typed json and the `json()` function to convert outgoing binary-typed jsonb. The example is expanded to show both of these approaches.

Note that both approaches use the same string-typed marshalling functions because the conversion to jsonb occurs within sqlite3, not within the Go code. SQLite docs state that the binary format is internal and applications shouldn't try to generate it: https://sqlite.org/json1.html#jsonb

Fix json example

…op-types

Add missing virtual table constraint op constants

- Replace len(args[start:start+na]) > 0 with na > 0 to avoid slice bounds check
- Use range loops instead of manual index loops for cols/decltype slices
- Use range variable v.Ordinal instead of re-indexing args[i].Ordinal
- Add bounds hint for decltype access in nextSyncLocked loop

Eliminate unnecessary bounds checks in hot paths