Thanks for stopping by to let us know something could be better!

PLEASE READ: If you have a support contract with Google, please create an issue in the support console instead of filing on GitHub. This will ensure a timely response.

Please run down the following list and make sure you've tried the usual "quick fixes":

• Search the issues already opened: https://github.com/googleapis/google-api-python-client/issues
• Search StackOverflow: https://stackoverflow.com/questions/tagged/google-cloud-platform+python

If you are still having issues, please be sure to include as much information as possible:

Environment details

• OS type and version:
• Python version: python --version
• pip version: pip --version
• google-api-python-client version: pip show google-api-python-client

Steps to reproduce

1. You can access typo in docstring.
   a https://github.com/googleapis/google-api-python-client/blob/main/googleapiclient/_helpers.py#L45
   b https://github.com/googleapis/google-api-python-client/blob/main/googleapiclient/discovery.py#L331
2. You can also access unnecessary word in docstring.
   a https://github.com/googleapis/google-api-python-client/blob/main/googleapiclient/_helpers.py#L97
   b https://github.com/googleapis/google-api-python-client/blob/main/googleapiclient/_helpers.py#L105

Code example

- 1.a def fn(pos1, *, kwonly1=None, kwonly1=None): -> def fn(pos1, *, kwonly1=None, kwonly2=None):
- 1.b attemnting -> attempting
- 2.a parameters after the this index must be -> parameters after this index must be
- 2.b TypeError: if a key-word only argument is provided as a positional -> TypeError: if a keyword-only argument is provided as a positional
    - Since keyword-only is already used in this docstring as an adjective, it's better to modify to it for consistency.

Stack trace

irrelevant

Making sure to follow these steps will guarantee the quickest resolution possible.

Thanks!