I'm not fully sure what's happening here, the same codebase started behaving differently once I've reinstalled my Ubuntu from 18.04 to 20.04 but maybe that's unrelated.

I'm using RIO.Process to run my python subprocess. The python I'm trying to run is located in virtualenv:

$ ls -lah /home/kb/workspace/emotive_conjugations/venv/bin/python
lrwxrwxrwx 1 kb kb 16 Apr 25 23:23 /home/kb/workspace/emotive_conjugations/venv/bin/python -> /usr/bin/python3

Once I'm running that python, I get an error, because what it actually does is it ends up running /usr/bin/python3 instead, because it's calling the findExecutable to resolve the name internally:

λ RIO.Prelude.Simple.runSimpleApp (RIO.Process.findExecutable "/home/kb/workspace/emotive_conjugations/venv/bin/python")
Right "/usr/bin/python3.8"

So, my question is, who is wrong here and how should I call a virtualenv'ed python executable properly? Thanks!