Hi,
I have some parsing issues using version 2.0.6.
It seems the problem occurs when I use std::enable_if_t macro helper in templates

There is not problem using std::enable_if like:

template < typename T , typename std::enable_if<std::is_base_of<BaseT, T>::value, int>::type = 0 >
class A
{
....
};

But parsing fails if using similar but simplified syntax using std::enable_if_t :

template < typename T ,  std::enable_if_t<std::is_base_of<BaseT, T>::value, int> = 0 > 
class A
{
....
};

Yo can see it usage at the "Notes" section at https://en.cppreference.com/w/cpp/types/enable_if

Both syntax have similar functionality, only that enable_if_t adds the "template" and ":type" on it definition (can see a type_traits header file), so both "template" and ":type" are not needed when used.
std::enable_if_t helper is specified since C++14 ( according to cppreference )

It's expected both alternatives to be recognized, but only the fist one is.