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lectures/classical_filtering.md

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@@ -172,7 +172,7 @@ or
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```{math}
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:label: eq_55
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x_t = \sum^{t-1}_{j=0} L^{-1}_{t,t-j}\, \varepsilon_{t-j}\
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x_t = \sum^{t-1}_{j=0} L^{-1}_{t,t-j}\, \varepsilon_{t-j}
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```
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where $L^{-1}_{i,j}$ denotes the $i,j$ element of $L^{-1}$.

lectures/opt_tax_recur.md

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@@ -74,6 +74,9 @@ import matplotlib.pyplot as plt
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## A Competitive Equilibrium with Distorting Taxes
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At time $t \geq 0$ a random variable $s_t$ belongs to a time-invariant
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set ${\cal S} = [1, 2, \ldots, S]$.
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For $t \geq 0$, a history $s^t = [s_t, s_{t-1}, \ldots, s_0]$ of an
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exogenous state $s_t$ has joint probability density $\pi_t(s^t)$.
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{u_c(s^{t}) \over u_c(s^0)}
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```
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(The stochastic process $\{q_t^0(s^t)\}$ is an instance of what finance economists call a *stochastic discount factor* process.)
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Using the first-order conditions {eq}`LSA_taxr` and {eq}`LS101` to eliminate
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taxes and prices from {eq}`TS_bcPV2`, we derive the *implementability condition*
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Given an initial government debt $b_0$, we want to maximize $J$
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with respect to $\{c_t(s^t), n_t(s^t); \forall s^t \}_{t\geq0}$ and to minimize with respect
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to $\{\theta(s^t); \forall s^t \}_{t\geq0}$.
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to $\Phi$ and with respect to $\{\theta(s^t); \forall s^t \}_{t\geq0}$.
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The first-order conditions for the Ramsey problem for periods $t \geq 1$ and $t=0$, respectively, are
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where we have imposed conditions {eq}`feas1_opt_tax` and {eq}`TSs_techr_opt_tax`.
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Equation {eq}`TS_barg` is one equation that can be solved to express the
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unknown $c$ as a function of the exogenous variable $g$.
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unknown $c$ as a function of the exogenous variable $g$ and the Lagrange multiplier $\Phi$.
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We also know that time $t=0$ quantities $c_0$ and $n_0$ satisfy
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```
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Notice that a counterpart to $b_0$ does *not* appear
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in {eq}`TS_barg`, so $c$ does not depend on it for $t \geq 1$.
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in {eq}`TS_barg`, so $c$ does not *directly* depend on it for $t \geq 1$.
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But things are different for time $t=0$.
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An analogous argument for the $t=0$ equations {eq}`eqFONCRamsey0` leads
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to one equation that can be solved for $c_0$ as a function of the
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pair $(g(s_0), b_0)$.
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pair $(g(s_0), b_0)$ and the Lagrange multiplier $\Phi$.
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These outcomes mean that the following statement would be true even when
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government purchases are history-dependent functions $g_t(s^t)$ of the
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variable $b_t$ that influences $c_t$ and $n_t$ for
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$t \geq 1$.
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The absence of $b_t$ as a determinant of the Ramsey allocation for
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The absence of $b_t$ as a direct determinant of the Ramsey allocation for
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$t \geq 1$ and its presence for $t=0$ is a symptom of the
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*time-inconsistency* of a Ramsey plan.
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Of course, $b_0$ affects the Ramsey allocation for $t \geq 1$ *indirectly* through
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its effect on $\Phi$.
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$\Phi$ has to take a value that assures that
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the household and the government’s budget constraints are both
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satisfied at a candidate Ramsey allocation and price system associated
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We maintain these assumptions throughout the remainder of this lecture.
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### Determining the Multiplier
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### Determining the Lagrange Multiplier
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We complete the Ramsey plan by computing the Lagrange multiplier $\Phi$
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on the implementability constraint {eq}`TSs_cham1`.
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$x_t$ being analogous to the price of the asset at time $t$.
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We learned earlier that for a Ramsey allocation
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$c_t(s^t), n_t(s^t)$ and $b_t(s_t|s^{t-1})$, and therefore
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$c_t(s^t), n_t(s^t)$, and $b_t(s_t|s^{t-1})$, and therefore
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also $x_t(s^t)$, are each functions of $s_t$ only, being
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independent of the history $s^{t-1}$ for $t \geq 1$.
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where $s'$ denotes a next period value of $s$ and
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$x'(s')$ denotes a next period value of $x$.
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Equation {eq}`LSA_budget2` is easy to solve for $x(s)$ for
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Given $n(s)$ for $s = $, equation {eq}`LSA_budget2` is easy to solve for $x(s)$ for
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$s = 1, \ldots , S$.
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If we let $\vec n, \vec g, \vec x$
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In summary, when $g_t$ is a time-invariant function of a Markov state
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$s_t$, a Ramsey plan can be constructed by solving $3S +3$
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equations in $S$ components each of $\vec c$, $\vec n$, and
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equations for $S$ components each of $\vec c$, $\vec n$, and
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$\vec x$ together with $n_0, c_0$, and $\Phi$.
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### Time Inconsistency
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### Specification with CRRA Utility
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In our calculations below and in a {doc}`subsequent lecture <amss>` based on an extension of the Lucas-Stokey model
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In our calculations below and in a {doc}`subsequent lecture <amss>` based on an *extension* of the Lucas-Stokey model
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by Aiyagari, Marcet, Sargent, and Seppälä (2002) {cite}`aiyagari2002optimal`, we shall modify the one-period utility function assumed above.
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(We adopted the preceding utility specification because it was the one used in the original {cite}`LucasStokey1983` paper)
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(We adopted the preceding utility specification because it was the one used in the original Lucas-Stokey paper {cite}`LucasStokey1983`. We shall soon revert to that specification in a subsequent section.)
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We will modify their specification by instead assuming that the representative agent has utility function
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```{math}
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:label: opt_tax_eqn_10
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b_0 + g_0 = \tau_0 (c_0 + g_0) + \frac{\bar b}{R_0}
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b_0 + g_0 = \tau_0 (c_0 + g_0) + \beta \sum_{s=1}^S \Pi(s | s_0) \frac{u_c(s)}{u_{c,0}} b_1(s)
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```
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where $R_0$ is the gross interest rate for the Markov state $s_0$ that is assumed to prevail at time $t =0$
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and $\tau_0$ is the time $t=0$ tax rate.
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where $\tau_0$ is the time $t=0$ tax rate.
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In equation {eq}`opt_tax_eqn_10`, it is understood that
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```{math}
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:nowrap:
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\begin{aligned}
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\tau_0 = 1 - \frac{u_{l,0}}{u_{c,0}} \\
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R_0 = \beta \sum_{s=1}^S \Pi(s | s_0) \frac{u_c(s)}{u_{c,0}}
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\tau_0 = 1 - \frac{u_{l,0}}{u_{c,0}}
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\end{aligned}
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```
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## Recursive Formulation of the Ramsey Problem
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$x_t(s^t) = u_c(s^t) b_t(s_t | s^{t-1})$ in equation {eq}`LSA_budget`
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We now temporarily revert to Lucas and Stokey's specification.
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We start by noting that $x_t(s^t) = u_c(s^t) b_t(s_t | s^{t-1})$ in equation {eq}`LSA_budget`
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appears to be a purely “forward-looking” variable.
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But $x_t(s^t)$ is a also a natural candidate for a state variable in
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a recursive formulation of the Ramsey problem.
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But $x_t(s^t)$ is a natural candidate for a state variable in
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a recursive formulation of the Ramsey problem, one that records history-dependence and so is
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``backward-looking''.
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### Intertemporal Delegation
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To express a Ramsey plan recursively, we imagine that a time $0$
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Ramsey planner is followed by a sequence of continuation Ramsey planners
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at times $t = 1, 2, \ldots$.
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A “continuation Ramsey planner” at times $t \geq 1$ has a
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different objective function and faces different constraints and state variabls than does the
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A “continuation Ramsey planner” at time $t \geq 1$ has a
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different objective function and faces different constraints and state variables than does the
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Ramsey planner at time $t =0$.
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A key step in representing a Ramsey plan recursively is
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continuation Ramsey planners do not.
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The time $0$ Ramsey planner
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hands a state-contingent function that make $x_1$ a function of $s_1$ to a time $1$
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hands a state-contingent function that make $x_1$ a function of $s_1$ to a time $1$, state $s_1$
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continuation Ramsey planner.
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These lines of delegated authorities and
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responsibilities across time express the continuation Ramsey planners’
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obligations to implement their parts of the original Ramsey plan,
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obligations to implement their parts of an original Ramsey plan that had been
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designed once-and-for-all at time $0$.
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### Two Bellman Equations
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* Let $V(x, s)$ be the value of a **continuation Ramsey plan** at $x_t = x, s_t =s$ for $t \geq 1$.
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* Let $W(b, s)$ be the value of a **Ramsey plan** at time $0$ at $b_0=b$ and $s_0 = s$.
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We work backward by presenting a Bellman equation for
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We work backward by preparing a Bellman equation for
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$V(x,s)$ first, then a Bellman equation for $W(b,s)$.
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### The Continuation Ramsey Problem
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where maximization over $n$ and the $S$ elements of
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$x'(s')$ is subject to the single implementability constraint for
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$t \geq 1$.
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$t \geq 1$:
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```{math}
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:label: LSA_Bellman1cons
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### The Ramsey Problem
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The Bellman equation for the time $0$ Ramsey planner is
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The Bellman equation of the time $0$ Ramsey planner is
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```{math}
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The value function $V(x_t, s_t)$ of the time $t$
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continuation Ramsey planner equals
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$E_t \sum_{\tau = t}^\infty \beta^{\tau - t} u(c_t, l_t)$, where
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the consumption and leisure processes are evaluated along the original
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consumption and leisure processes are evaluated along the original
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time $0$ Ramsey plan.
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### First-Order Conditions
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Attach a Lagrange multiplier $\Phi_1(x,s)$ to constraint {eq}`LSA_Bellman1cons` and a
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Lagrange multiplier $\Phi_0$ to constraint {eq}`Bellman2cons`.
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Time $t \geq 1$: the first-order conditions for the time $t \geq 1$ constrained
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Time $t \geq 1$: First-order conditions for the time $t \geq 1$ constrained
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maximization problem on the right side of the continuation Ramsey
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planner’s Bellman equation {eq}`LSA_Bellman1` are
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### State Variable Degeneracy
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Equations {eq}`LSAx0` and {eq}`LSAn0` imply that $\Phi_0 = \Phi_1$
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Equations {eq}`LSAenv` and {eq}`LSAx0` imply that $\Phi_0 = \Phi_1$
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and that
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```{math}
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## Examples
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We return to the setup with CRRA preferences described above.
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### Anticipated One-Period War
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This example illustrates in a simple setting how a Ramsey planner manages risk.

lectures/smoothing.md

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Please note that
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$$
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E_t b_{t+1} = \int \phi_{t+1}(x_{t+1} | A x_t, C C') b_{t+1}(x_{t+1}) d x_{t+1}
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\beta E_t b_{t+1} = \beta \int \phi_{t+1}(x_{t+1} | A x_t, C C') b_{t+1}(x_{t+1}) d x_{t+1}
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$$
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which verifies that $E_t b_{t+1}$ is the **value** of time $t+1$ state-contingent claims on time $t+1$ consumption issued by the consumer at time $t$
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or
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$$
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\beta E_t b_{t+1} = \int q_{t+1}(x_{t+1}| x_t) b_{t+1}(x_{t+1}) d x_{t+1}
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$$
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which verifies that $\beta E_t b_{t+1}$ is the **value** of time $t+1$ state-contingent claims on time $t+1$ consumption issued by the consumer at time $t$
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We can solve the time $t$ budget constraint forward to obtain
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But in the complete markets version, it is tractable to assume a more general utility function that satisfies $u' > 0$ and $u'' < 0$.
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The first-order conditions for the consumer's problem with complete
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First-order conditions for the consumer's problem with complete
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markets and our assumption about Arrow securities prices are
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$$

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