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Aragas
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Jan 8, 2026
| result.overrideInstructions?.forEach((instr) => { | ||
| const key = (instr.source ?? instr.type).toUpperCase(); | ||
| let key = instr.source ?? instr.type; | ||
| if (key == null) { |
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We only expect null? undefined isn't possible?
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key == null will handle both undefined and null
Aragas
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Jan 8, 2026
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fixes #19143