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6.4.cpp
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65 lines (58 loc) · 1.41 KB
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/*
* 题目名称：数制转换
* 题目来源：北京大学复试上机题
* 题目链接：http://t.cn/AiCu6ne4
* 代码作者：杨泽邦(炉灰)
*/
#include <iostream>
#include <cstdio>
#include <vector>
using namespace std;
char IntToChar(int x) { //数字变成字符
if (x < 10) {
return x + '0';
} else {
return x - 10 + 'A';
}
}
int CharToInt(char c) { //字符变成数字
if ('0' <= c && c <= '9') {
return c - '0';
} else if ('A' <= c && c <= 'Z') {
return c - 'A' + 10;
} else {
return c - 'a' + 10;
}
}
long long Convert2Ten(string str, int x) { //x进制转换10进制
long long number = 0;
for (int i = 0; i < str.size(); ++i) {
number *= x;
number += CharToInt(str[i]);
}
return number;
}
void Convert2Target(long long n, int x) { //10进制转换成为x进制
vector<char> answer;
if (n == 0) {
answer.push_back('0');
} else {
while (n != 0) {
answer.push_back(IntToChar(n % x));
n /= x;
}
}
for (int i = answer.size() - 1; i >= 0; --i) {
printf("%c", answer[i]);
}
printf("\n");
}
int main() {
int a, b;
string str;
while (cin >> a >> str >> b) {
long long number = Convert2Ten(str, a);
Convert2Target(number, b);
}
return 0;
}