Sorting a dictionary by value is a common task in Python and we will see different ways of how can accomplish this task. Also, sorting a dictionary with respect to keys is simpler than sorting it by values.<\/p>\n\n\n\n
This is the most straightforward method to sort a dictionary by its value. In this approach, we first sort the values of the dictionary in ascending order. We then loop through the sorted values and for each sorted value, we loop through the keys of the dictionary when we find a key with a value that matches the current sorted value, we add this key-value pair to the new dictionary that we have created to store the answer. In this way, we keep on adding all the key-value pairs in the newly created dictionary and finally print the sorted dictionary.<\/p>\n\n\n\n
dict1 = {\"Python\":3, \"Java\": 2, \"JavaScript\": 1, \"C++\": 5, \"Ruby\":4}\nsorted_values = sorted(dict1.values()) # Sort the values of original dictionary in ascending order\nsorted_dict = {} # Create a new dictionary to store the final result\n\nfor i in sorted_values: \n for k in dict1.keys(): \n if dict1[k] == i: # if the value is same as the sorted value\n sorted_dict[k] = dict1[k] # add it to the new dictionary \n break\nprint(sorted_dict)<\/pre><\/div>\n\n\n\nOutput:<\/strong><\/p>\n\n\n\n{'JavaScript': 1, 'Java': 2, 'Python': 3, 'Ruby': 4, 'C++': 5}<\/strong><\/pre>\n\n\n\n