{"id":24107,"date":"2023-01-22T15:36:40","date_gmt":"2023-01-22T10:06:40","guid":{"rendered":"https:\/\/copyassignment.com\/?p=24107"},"modified":"2023-01-22T15:36:42","modified_gmt":"2023-01-22T10:06:42","slug":"python-reverse-a-string-without-recursion","status":"publish","type":"post","link":"https:\/\/copyassignment.com\/python-reverse-a-string-without-recursion\/","title":{"rendered":"Python | Reverse a string without recursion"},"content":{"rendered":"\n

Let us now see all the methods to solve Python programs to reverse a string without recursion.<\/p>\n\n\n\n

Method 1: Using the loop<\/h2>\n\n\n\n
<\/span><\/div>
def rev_my_string(s):\n\tstr = \"\"\n\tfor i in s:\n\t\tstr = i + str\n\treturn str\n\ns = input(\">> Enter the string you want to reverse: \")\nprint(\"\\n\")\n\nprint(\">> The original string is : \", end=\"\")\nprint(s)\nprint(\"\\n\")\n\nprint(\">> The reversed string(using recursion) is : \", end=\"\")\nprint(rev_my_string(s))<\/pre><\/div>\n\n\n\n
Output<\/strong><\/p>\n\n\n\n
>> Enter the string you want to reverse: tnemngissAypoC - nohtyP fo s'GO eht era ew\n\n>> The original string is : tnemngissAypoC - nohtyP fo s'GO eht era ew\n\n>> The reversed string(without using recursion) is : we are the OG's of Python - CopyAssignment<\/code><\/pre>\n\n\n\n
Explanation<\/strong><\/p>\n\n\n\n
We used the for loop and inside the for loop, we assigned the value that is stored in ” i “<\/strong> to the str variable. In the first iteration, the str will be empty but as the values accessed by the ” i “<\/strong><\/strong>will be stored, it will start forming the reversed string.<\/p>\n\n\n\n
Method 2: Using the concept of stack<\/h2>\n\n\n\n
<\/span><\/div>
def make_a_stack():\n\tstack = []\n\treturn stack\ndef check_size(stack):\n\treturn len(stack)\ndef check_stack_empty(stack):\n\tif check_size(stack) == 0:\n\t\treturn true\ndef push_to_stack(stack, item):\n\tstack.append(item)\ndef pop(stack):\n\tif check_stack_empty(stack):\n\t\treturn\n\treturn stack.pop()\ndef rev_my_string(string):\n\tn = len(string)\n\tstack = make_a_stack()\n\tfor i in range(0, n, 1):\n\t\tpush_to_stack(stack, string[i])\n\tstring = \"\"\n\tfor i in range(0, n, 1):\n\t\tstring += pop(stack)\n\treturn string\ns = input(\">> Enter the string you want to reverse: \")\nprint(\"\\n\")\nprint(\">> The original string is : \", end=\"\")\nprint(s)\nprint(\"\\n\")\nprint(\">> The reversed string(using recursion) is : \", end=\"\")\nprint(rev_my_string(s))<\/pre><\/div>\n\n\n\n
Explanation<\/strong><\/p>\n\n\n\n
In this method, we declared 6 types of functions. Each function will handle some or the other thing.
The main logic behind using stack in this is not the stack data structure. As in stack data structure, where can perform push and pop, those concepts we will be using here to solve the given problem.<\/p>\n\n\n\n
At first, the string is passed on to the rev_my_string<\/strong> function. Here the length is determined and a stack is defined. make_a_stack<\/strong> is used to make a stack, check_size <\/strong>is used to check the size of the stack, check_stack_empty<\/strong> is used to check whether the stack is empty or not, push_to_stack<\/strong> is used to push the elements and finally, pop()<\/strong> is used to delete any element. These continuous calling of function is basically done to perform the operations in the stack.<\/p>\n\n\n\n
Method 3: Using string slicing concept<\/h2>\n\n\n\n
<\/span><\/div>
def rev_my_string(string):\n\tstring = string[::-1]\n\treturn string\n\ns = input(\">> Enter the string you want to reverse: \")\nprint(\"\\n\")\n\nprint(\">> The original string is : \", end=\"\")\nprint(s)\nprint(\"\\n\")\n\nprint(\">> The reversed string(using recursion) is : \", end=\"\")\nprint(rev_my_string(s))<\/pre><\/div>\n\n\n\n
Explanation:<\/strong><\/p>\n\n\n\n
Here we used the string-slicing concept. We direct used the negative indexing concept.<\/p>\n\n\n\n
Method 4: Using the reverse() function<\/h2>\n\n\n\n
<\/span><\/div>
def rev_my_string(string):\n    string = list(string)\n    string.reverse()\n    return \"\".join(string)\n \ns = input(\">> Enter the string you want to reverse: \")\nprint(\"\\n\")\nprint(\">> The original string is : \", end=\"\")\nprint(s)\nprint(\"\\n\")\nprint(\">> The reversed string(using recursion) is : \", end=\"\")\nprint(rev_my_string(s))<\/pre><\/div>\n\n\n\n
Explanation<\/strong><\/p>\n\n\n\n
Here we used the built-in function named reverse(). We passed on our string to the given built-in function and then joined it using join().<\/p>\n\n\n\n
Method 5: Using the concept of list comprehension<\/h2>\n\n\n\n
<\/span><\/div>
def rev_my_string(string):\n\tstring = [string[i] for i in range(len(string)-1, -1, -1)]\n\treturn \"\".join(string)\n\ns = input(\">> Enter the string you want to reverse: \")\nprint(\"\\n\")\n\nprint(\">> The original string is : \", end=\"\")\nprint(s)\nprint(\"\\n\")\n\nprint(\">> The reversed string(using recursion) is : \", end=\"\")\nprint(rev_my_string(s))<\/pre><\/div>\n\n\n\n
Explanation:<\/strong><\/p>\n\n\n\n
In this method, we used a one-liner to solve this problem\/ The first part in the list comprehension is expression then for loop, and finally our conditional statement. When you wish to make a new list based on the values of an existing list, list comprehension offers a more concise syntax. <\/p>\n\n\n\n
Here is the end of our article. We hope it had new ways and concepts to boost your Python knowledge.<\/p>\n","protected":false},"excerpt":{"rendered":"
Let us now see all the methods to solve Python programs to reverse a string without recursion. Method 1: Using the loop Output Explanation We…<\/p>\n","protected":false},"author":62,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[22,1930],"tags":[],"class_list":["post-24107","post","type-post","status-publish","format-standard","hentry","category-allcategorites","category-programs-in-python","wpcat-22-id","wpcat-1930-id"],"_links":{"self":[{"href":"https:\/\/copyassignment.com\/wp-json\/wp\/v2\/posts\/24107","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/copyassignment.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/copyassignment.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/copyassignment.com\/wp-json\/wp\/v2\/users\/62"}],"replies":[{"embeddable":true,"href":"https:\/\/copyassignment.com\/wp-json\/wp\/v2\/comments?post=24107"}],"version-history":[{"count":0,"href":"https:\/\/copyassignment.com\/wp-json\/wp\/v2\/posts\/24107\/revisions"}],"wp:attachment":[{"href":"https:\/\/copyassignment.com\/wp-json\/wp\/v2\/media?parent=24107"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/copyassignment.com\/wp-json\/wp\/v2\/categories?post=24107"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/copyassignment.com\/wp-json\/wp\/v2\/tags?post=24107"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}