{"id":1805,"date":"2022-01-14T19:54:37","date_gmt":"2022-01-14T14:24:37","guid":{"rendered":"https:\/\/cbsepython.in\/?p=1805"},"modified":"2022-06-12T13:18:49","modified_gmt":"2022-06-12T07:48:49","slug":"computer-science-sample-paper-term-2","status":"publish","type":"post","link":"https:\/\/cbsepython.in\/computer-science-sample-paper-term-2\/","title":{"rendered":"Solved Computer Science Sample Paper Term 2 Class 12"},"content":{"rendered":"

Computer Science Sample Paper Term 2 Class 12<\/span><\/h2>\n

Sample Question Paper<\/span><\/p>\n

COMPUTER SCIENCE (Code: 083)<\/span><\/p>\n

Maximum Marks: 35 \/Time: 2 hours<\/span><\/p>\n

 <\/p>\n

General Instructions<\/span><\/p>\n

*\u00a0 The question paper is divided into 3 sections \u2013 A, B and C<\/span><\/p>\n

* Section A, consists of 7 questions (1-7). Each question carries 2 marks.<\/span><\/p>\n

* Section B, consists of 3 questions (8-10). Each question carries 3 marks.<\/span><\/p>\n

* Section C, consists of 3 questions (11-13). Each question carries 4 marks.<\/span><\/p>\n

* Internal choices have been given for question numbers 7, 8 and 12.<\/span><\/p>\n

 <\/p>\n

Section -A<\/span><\/strong><\/p>\n

Each question carries 2 marks<\/span><\/strong><\/p>\n

 <\/p>\n

1. Give any two characteristics of stacks.<\/strong><\/span><\/p>\n

Ans: Characteristics of Stacks:<\/span><\/p>\n

> It is a LIFO data structure<\/span><\/p>\n

> The insertion and deletion happens at one end i.e. from the top of the stack<\/span><\/p>\n

 <\/p>\n

2. (i) Expand the following: SMTP , XML<\/span><\/strong><\/p>\n

Ans: SMTP : Simple Mail Transfer Protocol<\/span>
\nXML: Extensible Mark Up Language<\/span><\/p>\n

 <\/p>\n

(ii) Out of the following, which is the fastest wired and wireless medium of transmission?<\/span><\/strong><\/p>\n

Infrared, coaxial cable, optical fibre, microwave, Ethernet cable<\/span><\/p>\n

Ans: Wired- optical fibre<\/span>
\nWireless \u2013 microwave<\/span><\/p>\n

 <\/p>\n

Also Check:<\/span><\/h1>\n

Computer Science Sample Paper Class 12 Term 2 Set 1<\/a><\/span><\/h2>\n

Computer Science Sample Paper Class 12 Term 2 Set 2<\/a><\/span><\/h2>\n

Computer Science Sample Paper Class 12 Term 2\u00a0Set 3<\/a><\/span><\/h2>\n

Computer Science Sample Paper Class 12 Term 2\u00a0Set 4<\/a><\/span><\/h2>\n

Computer Science Sample Paper Class 12 Term 2 Set 5<\/a><\/span><\/h2>\n

Computer Science Sample Paper Class 12 Term 2 set 6<\/a><\/span><\/h2>\n

Computer Networking Question and Answer<\/a><\/span><\/h2>\n

Important Question Answer for Term 2 Exam<\/a><\/span><\/h2>\n

Database Management System Questions with Answer<\/span><\/a><\/h2>\n

 <\/p>\n

3. Differentiate between char(n) and varchar(n) data types with respect to databases.<\/span><\/strong><\/p>\n

Ans: <\/span><\/p>\n

char(n):<\/span><\/strong><\/p>\n

> stores a fixed length string between 1 and 255 characters<\/span><\/p>\n

> if the value is of smaller length, adds blank spaces<\/span><\/p>\n

> some space is wasted<\/span><\/p>\n

varchar(n) :<\/span><\/strong><\/p>\n

> stores a variable length string<\/span><\/p>\n

> no blanks are added even if value is of smaller length<\/span><\/p>\n

> no wastage of space<\/span><\/p>\n

4. A resultset is extracted from the database using the cursor object (that has been already created) by giving the following statement.<\/span><\/strong><\/p>\n

Mydata=cursor.fetchone()<\/span><\/p>\n

(a) How many records will be returned by fetchone() method?<\/span><\/strong><\/p>\n

Ans: One record<\/span><\/p>\n

(b) What will be the datatype of Mydata object after the given command is executed?<\/span><\/strong><\/p>\n

Ans: tuple<\/span><\/p>\n

 <\/p>\n

5. Write the output of the queries (a) to (d) based on the table, Furniture given below:<\/span><\/strong><\/p>\n

 <\/p>\n

Table: FURNITURE<\/span><\/strong><\/p>\n\n\n\n\n\n\n\n\n\n
FID<\/span><\/td>\nNAME<\/span><\/td>\nDATEOFPURCHASE<\/span><\/td>\nCOST<\/span><\/td>\nDISCOUNT<\/span><\/td>\n<\/tr>\n
B001<\/span><\/td>\nDouble Bed<\/span><\/td>\n03-Jan-2018<\/span><\/td>\n45000<\/span><\/td>\n10<\/span><\/td>\n<\/tr>\n
T010<\/span><\/td>\nDining Table<\/span><\/td>\n10-Mar-2020<\/span><\/td>\n51000<\/span><\/td>\n5<\/span><\/td>\n<\/tr>\n
B004<\/span><\/td>\nSingle Bed<\/span><\/td>\n19-Jul-2021<\/span><\/td>\n22000<\/span><\/td>\n0<\/span><\/td>\n<\/tr>\n
C003<\/span><\/td>\nLong Back Chair<\/span><\/td>\n30-Dec-2016<\/span><\/td>\n12000<\/span><\/td>\n3<\/span><\/td>\n<\/tr>\n
T006<\/span><\/td>\nConsole Table<\/span><\/td>\n17-Nov-2021<\/span><\/td>\n15000<\/span><\/td>\n12<\/span><\/td>\n<\/tr>\n
B006<\/span><\/td>\nBunk Bed<\/span><\/td>\n01-Jan-2021<\/span><\/td>\n28000<\/span><\/td>\n14<\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

 <\/p>\n

(a) SELECT SUM(DISCOUNT) FROM FURNITURE WHERE COST>15000;<\/span><\/strong><\/p>\n

Ans: 29<\/span><\/p>\n

 <\/p>\n

(b) SELECT MAX(DATEOFPURCHASE) FROM FURNITURE;<\/span><\/strong><\/p>\n

Ans: 19-Jul-2021<\/span><\/p>\n

 <\/p>\n

(c) SELECT * FROM FURNITURE WHERE DISCOUNT>5 AND FID LIKE “T%”;<\/span><\/strong><\/p>\n

Ans:<\/span><\/p>\n\n\n\n
T006<\/span><\/td>\nConsole Table<\/span><\/td>\n17-Nov-2019<\/span><\/td>\n15000<\/span><\/td>\n12<\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

 <\/p>\n

(d) SELECT DATEOFPURCHASE FROM FURNITURE WHERE NAME IN (“Dining Table”, “Console Table”);<\/span><\/strong><\/p>\n

Ans:\u00a0<\/span><\/p>\n

10-Mar- 2020<\/span>
\n17-Nov-2019<\/span><\/p>\n

 <\/p>\n

6. (i) Which command is used to view the list of tables in a database?<\/span><\/strong><\/p>\n

Ans: SHOW TABLES;<\/span><\/p>\n

 <\/p>\n

(ii) Give one point of difference between an equi-join and a natural join.<\/span><\/strong><\/p>\n

Ans:<\/span><\/p>\n

Equi- join:<\/span><\/strong><\/p>\n

> The join in which columns from two tables are compared for equality<\/span><\/p>\n

> Duplicate columns are shown Natural Join<\/span><\/p>\n

> The join in which only one of the identical columns existing in both tables is present<\/span><\/p>\n

> No duplication of columns <\/span><\/p>\n

 <\/p>\n

7. Consider the table, MOVIEDETAILS given below:<\/span><\/strong><\/p>\n

Table: MOVIEDETAILS<\/span><\/strong><\/p>\n\n\n\n\n\n\n\n\n\n
MOVIEID<\/span><\/td>\nTITLE<\/span><\/td>\nLANGUAGE<\/span><\/td>\nRATING<\/span><\/td>\nPLATFORM<\/span><\/td>\n<\/tr>\n
M001<\/span><\/td>\nMinari<\/span><\/td>\nKorean<\/span><\/td>\n5<\/span><\/td>\nNetflix<\/span><\/td>\n<\/tr>\n
M004<\/span><\/td>\nMGR Magan<\/span><\/td>\nTamil<\/span><\/td>\n4<\/span><\/td>\nHotstar<\/span><\/td>\n<\/tr>\n
M010<\/span><\/td>\nKaagaz<\/span><\/td>\nHindi<\/span><\/td>\n3<\/span><\/td>\nZee5<\/span><\/td>\n<\/tr>\n
M011<\/span><\/td>\nHarry Potter<\/span><\/td>\nEnglish<\/span><\/td>\n4<\/span><\/td>\nPrime Video<\/span><\/td>\n<\/tr>\n
M015<\/span><\/td>\nUri<\/span><\/td>\nHindi<\/span><\/td>\n5<\/span><\/td>\nZee5<\/span><\/td>\n<\/tr>\n
M020<\/span><\/td>\nAvengers: Endgame<\/span><\/td>\nEnglish<\/span><\/td>\n4<\/span><\/td>\nHotstar<\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

 <\/p>\n

(a) Identify the degree and cardinality of the table.<\/span><\/strong><\/p>\n

Ans: Degree: 5, Cardinality: 6<\/span><\/p>\n

 <\/p>\n

(b) Which field should be made the primary key? Justify your answer.<\/span><\/strong><\/p>\n

Ans: MOVIEID should be made the primary key as it uniquely identifies each record of the table.\u00a0<\/span><\/p>\n

 <\/p>\n

OR<\/span><\/p>\n

(a) Identify the candidate key(s) from the table MOVIEDETAILS.<\/span><\/strong><\/p>\n

Ans: MOVIEID and TITLE<\/span><\/p>\n

 <\/p>\n

(b) Consider the table SCHEDULE given below:<\/span><\/strong><\/p>\n

Table: SCHEDULE<\/span><\/strong><\/p>\n\n\n\n\n\n\n\n
SLOTID<\/span><\/td>\nMOVIEID<\/span><\/td>\nTIMESLOT<\/span><\/td>\n<\/tr>\n
S001<\/span><\/td>\nM010<\/span><\/td>\n10 AM to 12 PM<\/span><\/td>\n<\/tr>\n
S002<\/span><\/td>\nM020<\/span><\/td>\n2 PM to 5 PM<\/span><\/td>\n<\/tr>\n
S003<\/span><\/td>\nM010<\/span><\/td>\n6 PM to 8 PM<\/span><\/td>\n<\/tr>\n
S004<\/span><\/td>\nM011<\/span><\/td>\n9 PM to 11 PM<\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

 <\/p>\n

Which field will be considered as the foreign key if the tables MOVIEDETAILS and SCHEDULE are related in a database?<\/span><\/strong><\/p>\n

Ans: MOVIEID<\/span><\/p>\n

 <\/p>\n

SECTION \u2013 B<\/span><\/strong><\/p>\n

Each question carries 3 marks<\/span><\/strong><\/p>\n

8. Julie has created a dictionary containing names and marks as key value pairs of 6 students. Write a program, with separate user defined functions to perform the following operations:<\/span><\/strong><\/p>\n

> Push the keys (name of the student) of the dictionary into a stack, where the corresponding value (marks) is greater than 75.<\/span><\/p>\n

> Pop and display the content of the stack.<\/span><\/p>\n

For example:<\/span><\/p>\n

If the sample content of the dictionary is as follows:<\/span><\/p>\n

R={“OM”:76, “JAI”:45, “BOB”:89, “ALI”:65, “ANU”:90, “TOM”:82}<\/span><\/p>\n

The output from the program should be:<\/span><\/p>\n

TOM ANU BOB OM<\/span><\/p>\n

 <\/p>\n

Ans:\u00a0<\/span><\/p>\n

R={“OM”:76, “JAI”:45, “BOB”:89,<\/span>
\n“ALI”:65, “ANU”:90, “TOM”:82}<\/span>
\ndef PUSH(S,N):<\/span>
\nS.append(N)<\/span>
\ndef POP(S):<\/span>
\nif S!=[]:<\/span>
\nreturn S.pop()<\/span>
\nelse:<\/span>
\nreturn None<\/span>
\nST=[]<\/span>
\nfor k in R:<\/span>
\nif R[k]>=75:<\/span>
\nPUSH(ST,k)<\/span>
\nwhile True:<\/span>
\nif ST!=[]:<\/span>
\nprint(POP(ST),end=” “)<\/span>
\nelse:<\/span>
\nbreak <\/span><\/p>\n

OR<\/span><\/p>\n

Alam has a list containing 10 integers. You need to help him create a program with separate user defined functions to perform the following operations based on this list.<\/span><\/strong><\/p>\n

> Traverse the content of the list and push the even numbers into a stack.<\/span><\/p>\n

> Pop and display the content of the stack.<\/span><\/p>\n

For Example:<\/span><\/p>\n

If the sample Content of the list is as follows:<\/span><\/p>\n

N=[12, 13, 34, 56, 21, 79, 98, 22, 35, 38]<\/span><\/p>\n

Sample Output of the code should be:<\/span><\/p>\n

38 22 98 56 34 12<\/span><\/p>\n

 <\/p>\n

Ans:<\/span><\/p>\n

N=[12, 13, 34, 56, 21, 79, 98, 22,<\/span>
\n35, 38]<\/span>
\ndef PUSH(S,N):<\/span>
\nS.append(N)<\/span>
\ndef POP(S):<\/span>
\nif S!=[]:<\/span>
\nreturn S.pop()<\/span>
\nelse:<\/span>
\nreturn None<\/span>
\nST=[]<\/span>
\nfor k in N:<\/span>
\nif k%2==0:<\/span>
\nPUSH(ST,k)<\/span>
\nwhile True:<\/span>
\nif ST!=[]:<\/span>
\nprint(POP(ST),end=” “)<\/span>
\nelse:<\/span>
\nbreak <\/span><\/p>\n

9. (i) A table, ITEM has been created in a database with the following fields:<\/span><\/strong><\/p>\n

ITEMCODE, ITEMNAME, QTY, PRICE<\/span><\/p>\n

Give the SQL command to add a new field, DISCOUNT (of type Integer) to the ITEM table.<\/span><\/p>\n

Ans: ALTER TABLE Item<\/span>
\nADD (Discount INT);<\/span><\/p>\n

 <\/p>\n

(ii) Categorize following commands into DDL and DML commands?<\/span><\/strong><\/p>\n

INSERT INTO, DROP TABLE, ALTER TABLE, UPDATE…SET<\/span><\/p>\n

Ans:\u00a0<\/span><\/p>\n

DDL: DROP TABLE, ALTER TABLE<\/span>
\nDML: INSERT INTO, UPDATE, SET<\/span><\/p>\n

 <\/p>\n

10. Charu has to create a database named MYEARTH in MYSQL.<\/span><\/strong><\/p>\n

She now needs to create a table named CITY in the database to store the records of various cities across the globe. The table CITY has the following structure:<\/span><\/p>\n

Table: CITY<\/span><\/strong><\/p>\n\n\n\n\n\n\n\n\n\n
FIELD NAME<\/span><\/td>\nDATA TYPE<\/span><\/td>\nREMARKS<\/span><\/td>\n<\/tr>\n
CITYCODE<\/span><\/td>\nCHAR(5)<\/span><\/td>\nPrimary Key<\/span><\/td>\n<\/tr>\n
CITYNAME<\/span><\/td>\nCHAR(30)<\/span><\/td>\n<\/td>\n<\/tr>\n
SIZE<\/span><\/td>\nINTEGER<\/span><\/td>\n<\/td>\n<\/tr>\n
AVGTEMP<\/span><\/td>\nINTEGER<\/span><\/td>\n<\/td>\n<\/tr>\n
POLLUTIONRATE<\/span><\/td>\nINTEGER<\/span><\/td>\n<\/td>\n<\/tr>\n
POPULATION<\/span><\/td>\nINTEGER<\/span><\/td>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

 <\/p>\n

Help her to complete the task by suggesting appropriate SQL commands.<\/span><\/p>\n

CREATE DATABASE MYEARTH;<\/span>
\nCREATE TABLE CITY (CITYCODE CHAR(5)PRIMARY KEY,<\/span>
\nCITYNAME CHAR(30),<\/span>
\nSIZE INT,<\/span>
\nAVGTEMP INT,<\/span>
\nPOPULATIONRATE INT,<\/span>
\nPOPULATION INT,);<\/span><\/p>\n

 <\/p>\n

Section C<\/span><\/strong><\/p>\n

Each question carries 4 marks<\/span><\/strong><\/p>\n

11. Write queries (a) to (d) based on the tables EMPLOYEE and DEPARTMENT given below:<\/span><\/strong><\/p>\n

Table: EMPLOYEE<\/span><\/p>\n\n\n\n\n\n\n\n\n
EMPID<\/span><\/td>\nNAME<\/span><\/td>\nDOB<\/span><\/td>\nDEPTID<\/span><\/td>\nDESIG<\/span><\/td>\nSALARY<\/span><\/td>\n<\/tr>\n
120<\/span><\/td>\nAlisha<\/span><\/td>\n23-Jan-1978<\/span><\/td>\nD001<\/span><\/td>\nManager<\/span><\/td>\n75000<\/span><\/td>\n<\/tr>\n
123<\/span><\/td>\nNitin<\/span><\/td>\n10-Oct-1977<\/span><\/td>\nD002<\/span><\/td>\nAO<\/span><\/td>\n59000<\/span><\/td>\n<\/tr>\n
129<\/span><\/td>\nNavjot<\/span><\/td>\n12-Jul-1971<\/span><\/td>\nD003<\/span><\/td>\nSupervisor<\/span><\/td>\n40000<\/span><\/td>\n<\/tr>\n
130<\/span><\/td>\nJimmy<\/span><\/td>\n30-Dec-1980<\/span><\/td>\nD004<\/span><\/td>\nSales Rep<\/span><\/td>\n<\/td>\n<\/tr>\n
131<\/span><\/td>\nFaiz<\/span><\/td>\n06-Apr-1984<\/span><\/td>\nD001<\/span><\/td>\nDep Manager<\/span><\/td>\n65000<\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

 <\/p>\n

 <\/p>\n

Table: DEPARTMENT<\/span><\/p>\n\n\n\n\n\n\n\n
DEPTID<\/span><\/td>\nDEPTNAME<\/span><\/td>\nFLOORNO<\/span><\/td>\n<\/tr>\n
D001<\/span><\/td>\nPersonal<\/span><\/td>\n4<\/span><\/td>\n<\/tr>\n
D002<\/span><\/td>\nAdmin<\/span><\/td>\n10<\/span><\/td>\n<\/tr>\n
D003<\/span><\/td>\nProduction<\/span><\/td>\n1<\/span><\/td>\n<\/tr>\n
D004<\/span><\/td>\nSales<\/span><\/td>\n3<\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

 <\/p>\n

(a) To display the average salary of all employees, department wise.<\/span><\/strong><\/p>\n

Ans: SELECT AVG(SALARY)<\/span>
\nFROM EMPLOYEE<\/span>
\nGROUP BY DEPTID;<\/span><\/p>\n

 <\/p>\n

(b) To display name and respective department name of each employee whose salary is more than 50000.<\/span><\/strong><\/p>\n

Ans:<\/span><\/p>\n

SELECT NAME, DEPTNAME<\/span>
\nFROM EMPLOYEE, DEPARTMENT<\/span>
\nWHERE<\/span>
\nEMPLOYEE.DEPTID=<\/span>
\nDEPARTMENT.DEPTID<\/span>
\nAND SALARY>50000;<\/span><\/p>\n

 <\/p>\n

(c) To display the names of employees whose salary is not known, in alphabetical order.<\/span><\/strong><\/p>\n

Ans:SELECT NAME FROM EMPLOYEE<\/span>
\nWHERE SALARY IS NULL<\/span>
\nORDER BY NAME;<\/span><\/p>\n

 <\/p>\n

(d) To display DEPTID from the table EMPLOYEE without repetition.<\/span><\/strong><\/p>\n

Ans:<\/span><\/p>\n

SELECT DISTINCT DEPTID<\/span>
\nFROM EMPLOYEE;<\/span><\/p>\n

 <\/p>\n

12. (i) Give two advantages and two disadvantages of star topology<\/span><\/strong><\/p>\n

Ans: <\/span><\/p>\n

Advantages<\/span><\/strong><\/p>\n

> Ease of service<\/span><\/p>\n

> Centralized control<\/span><\/p>\n

> Easy to diagnose faults<\/span><\/p>\n

> One device per connection<\/span><\/p>\n

Disadvantages<\/span><\/strong><\/p>\n

> long cable length<\/span><\/p>\n

> difficult to expand<\/span><\/p>\n

> central node dependency<\/span><\/p>\n

 <\/p>\n

OR<\/span><\/p>\n

Define the following terms:<\/span><\/strong><\/p>\n

www , web hosting<\/span><\/p>\n

Ans:\u00a0<\/span><\/p>\n

www: a set of protocols that allow you to access any document on the internet through the naming systems based on URLs<\/span><\/p>\n

Web hosting: Web hosting is a service that allows organizations and individuals to post a website or web page onto the server, which can be viewed by everyone on the Internet.<\/span><\/p>\n

 <\/p>\n

(ii)\u00a0How is packet switching different from circuit switching?<\/span><\/strong><\/p>\n

Ans:<\/span><\/p>\n

Packet switching:<\/span><\/strong><\/p>\n

> uses store and forward concept to send <\/span>messages<\/span><\/p>\n

> no physical path is actually establishes<\/span><\/p>\n

> message is divided into smaller parts, known <\/span>as packets and then sent forward<\/span><\/p>\n

> tight upper limit on block size<\/span><\/p>\n

> Each data unit knows only the final <\/span>receiver\u2019s address<\/span><\/p>\n

 <\/p>\n

Circuit switching<\/span><\/strong><\/p>\n

> physical connection is established between <\/span>sender and receiver<\/span><\/p>\n

> Each data unit knows the entire path from <\/span>sender to receiver<\/span><\/p>\n

> It does not follow store and forward <\/span>concept<\/span><\/p>\n

 <\/p>\n

13.\u00a0BeHappy Corporation has set up its new centre at Noida, Uttar Pradesh for its office and web-based activities. It has 4 blocks of buildings.<\/span><\/strong><\/p>\n

\"\"<\/p>\n

Distance between the various blocks is as follows:<\/span><\/strong><\/p>\n

A to B 40 m<\/span><\/p>\n

B to C 120m<\/span><\/p>\n

C to D 100m<\/span><\/p>\n

A to D 170m<\/span><\/p>\n

B to D 150m<\/span><\/p>\n

A to C 70m<\/span><\/p>\n

 <\/p>\n

Numbers of computers in each block<\/span><\/strong><\/p>\n

Block A – 25<\/span><\/p>\n

Block B – 50<\/span><\/p>\n

Block C – 125<\/span><\/p>\n

Block D – 10<\/span><\/p>\n

 <\/p>\n

(a) Suggest and draw the cable layout to efficiently connect various blocks of buildings within the Noida centre for connecting the digital devices.<\/span><\/strong><\/p>\n

Ans: Block B>Block A>Block C>Block D<\/span><\/p>\n

 <\/p>\n

(b) Suggest the placement of the following device with justification<\/span><\/strong><\/p>\n

    \n
  1. Repeater<\/span><\/li>\n
  2. Hub\/Switch<\/span><\/li>\n<\/ol>\n

    Ans: Repeater : between C and D as the distance <\/span>between them is 100 mts.<\/span><\/p>\n

    Hub\/ Switch : in each block as they help to share <\/span>data packets within the devices of the network in <\/span>each block<\/span><\/p>\n

     <\/p>\n

    (c) Which kind of network (PAN\/LAN\/WAN) will be formed if the Noida office is connected to its head office in Mumbai?<\/span><\/strong><\/p>\n

    Ans: WAN<\/span><\/p>\n

     <\/p>\n

    (d) Which fast and very effective wireless transmission medium should preferably be used to connect the head office at Mumbai with the centre at Noida?<\/span><\/strong><\/p>\n

    Ans: <\/span>Satellite<\/span><\/p>\n

     <\/p>\n

    Also Check:<\/span><\/h1>\n

    Computer Science Sample Paper Class 12 Term 2 Set 1<\/a><\/span><\/h2>\n

    Computer Science Sample Paper Class 12 Term 2 Set 2<\/a><\/span><\/h2>\n

    Computer Science Sample Paper Class 12 Term 2\u00a0Set 3<\/a><\/span><\/h2>\n

    Computer Science Sample Paper Class 12 Term 2\u00a0Set 4<\/a><\/span><\/h2>\n

    Computer Science Sample Paper Class 12 Term 2 Set 5<\/a><\/span><\/h2>\n

    Computer Science Sample Paper Class 12 Term 2 set 6<\/a><\/span><\/h2>\n

    Computer Networking Question and Answer<\/a><\/span><\/h2>\n

    Important Question Answer for Term 2 Exam<\/a><\/span><\/h2>\n

    Database Management System Questions with Answer<\/span><\/a><\/h2>\n

     <\/p>\n

     <\/p>\n","protected":false},"excerpt":{"rendered":"

    Computer Science Sample Paper Term 2 Class 12 Sample Question Paper COMPUTER SCIENCE (Code: 083) Maximum Marks: 35 \/Time: 2 hours   General Instructions *\u00a0 The question paper is divided into 3 sections \u2013 A, B and C * Section A, consists of 7 questions (1-7). Each question carries 2 marks. * Section B, consists […]<\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[16],"tags":[],"class_list":["post-1805","post","type-post","status-publish","format-standard","hentry","category-cbse-sample-papers-class-12"],"_links":{"self":[{"href":"https:\/\/cbsepython.in\/wp-json\/wp\/v2\/posts\/1805","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/cbsepython.in\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/cbsepython.in\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/cbsepython.in\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/cbsepython.in\/wp-json\/wp\/v2\/comments?post=1805"}],"version-history":[{"count":0,"href":"https:\/\/cbsepython.in\/wp-json\/wp\/v2\/posts\/1805\/revisions"}],"wp:attachment":[{"href":"https:\/\/cbsepython.in\/wp-json\/wp\/v2\/media?parent=1805"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/cbsepython.in\/wp-json\/wp\/v2\/categories?post=1805"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/cbsepython.in\/wp-json\/wp\/v2\/tags?post=1805"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}