Member since March 31, 2013

testietester

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testietester
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Slotted, Computers, Events, Networking, Probability, Combinatorics, Network, Aloha
My Recent Posts
 
Tue 2 Apr, 2013 09:44 pm - Thanks Mark! (view)
Mon 1 Apr, 2013 06:02 pm - Actually, using t = 3 and p = 1/2 I get: 3(0.5)(0.5)^(3-1) * 2(0.5)(0.5)^(2-1) * 1(0.5)(0.5)^(1-1) = 0.04375 That doesnt seem right. Anybody know what went wrong? I already checked my... (view)
Mon 1 Apr, 2013 05:55 pm - Thanks mark! +1 (view)
Mon 1 Apr, 2013 12:15 pm - So you're saying that it should be: P(1 node successful) * P(unsuccessful) * P(next node " ") * P(last node " ") = 3(0.5)(0.5)^(3-1) * [1-2(0.5)(0.5)^(2-1)] *... (view)
Sun 31 Mar, 2013 11:07 pm - @markr Thanks! But the problem I see with using the 2nd version is that I cannot extend it to t = 4. Unless I have the 4th one be 0(0.5)(0.5)^(0-1) = 0. Making the whole thing = 0.... (view)
Sun 31 Mar, 2013 02:35 pm - I'm trying to understand slotted ALOHA and I have a question regarding the probabilities. Slotted ALOHA works like this: You have nodes, ready to send "frames" of data. They... (view)
 
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