Mon 1 Apr, 2013 06:02 pm - Actually, using t = 3 and p = 1/2 I get:
3(0.5)(0.5)^(3-1) * 2(0.5)(0.5)^(2-1) * 1(0.5)(0.5)^(1-1) = 0.04375
That doesnt seem right. Anybody know what went wrong? I already checked my... (view)
Sun 31 Mar, 2013 11:07 pm - @markr
Thanks! But the problem I see with using the 2nd version is that I cannot extend it to t = 4. Unless I have the 4th one be 0(0.5)(0.5)^(0-1) = 0. Making the whole thing = 0.... (view)
Sun 31 Mar, 2013 02:35 pm - I'm trying to understand slotted ALOHA and I have a question regarding the probabilities.
Slotted ALOHA works like this: You have nodes, ready to send "frames" of data. They... (view)