Fri 4 Nov, 2011 04:56 pm - Ive been thinking a bit more, and it seems to be a lot more simple then I actually thought:
arg((z+i)/(z-1))=3pi/2
substitution:
arg(w)=3pi/2
then w = -ri with r being any positive number..
so... (view)
Fri 4 Nov, 2011 05:58 am - Hey all, Im studying for a calculus exam and Im kinda having a hard time with complex numbers. The assignment Im trying to solve is:
abs((z+i)/(z-1))=3pi/2.
I have no idea how to start, can... (view)
